[英]How to split list by certain repeated index in python
我有这个十进制值列表
[97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112] // more and more...
如何以这种方式拆分它:
[[97,98,99,100],[101,102,103,104],[105,106,107,108],[109,110,111,112]]
然后将十进制值转换为字符串,这样就可以像这样
['abcd','efgh','ijkl','mnop']
您可以使用列表理解来做到这一点:
a = [97,98,99,100,101,102,103,104,105,106,107,108,109,110,111,112]
[''.join(chr(j) for j in a[i:i+4]) for i in range(0, len(a), 4)]
Output:
['abcd', 'efgh', 'ijkl', 'mnop']
您可以对一个衬里使用嵌套生成器(列表)理解:
base = [97, 98, 99, 100, 101, 102, 103, 104,
105, 106, 107, 108, 109, 110, 111, 112]
y = ["".join((chr(k) for k in j))for j in (base[i:i+4]for i in range(0, len(base), 4))]
>>> y
['abcd', 'efgh', 'ijkl', 'mnop']
如果您使用floats
(小数)转换为 int :
y = ["".join((chr(int(k)) for k in j))for j in (base[i:i+4]for i in range(0, len(base), 4))]
# ^^^
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