我怎么能强迫它只串

Question

您好，我如何强制将 nname 设置为仅输入字符串，因为即使我输入数字，它仍然会继续到下一个 function 并且我只喜欢它是人名 nname= str(input()) 不起作用为什么我要问是否有其他选择可以让它只使用一个字符串

 print("Good Day Welcome To our Shop.")
mnu = ["Milktea","Foods", "Drinks", "Dessert"]
lsa = ["1.Matcha", "Taro", "Winter Melon", "Okinawa", "Chocolate",
     "Cheese Cake"]
fds  = {'Chicken'}
shot = ["tubig"]
mtms = ["ice cream"]
laht = []

print("Hi what would you like to be called, "
  "So we can inform you if your order is ready")


def cstmrinfo(name):

print("Okay " + name, "So what would you like to get " )
print(*mnu,sep = "\n")
nname=  input().lower()

def kuha_order():
 while True:
    order = input()

    if (order == "Milktea") or (order == "milktea"):
        print(lsa)
        laht.append(order)
        break
    elif (order == "Foods") or (order == "foods"):
        print(fds)
        laht.append(order)
        break
    elif (order == "Drinks") or (order == "drinks"):
         print(shot)
         laht.append(order)
         break
    elif (order == "Dessert") or (order == "dessert"):
         print(mtms)
         laht.append(order)
         break
    else:
     print("Sorry you input a thing that is not available on our menu,  "
           "Please Try again:")
     continue


def pnglhtn():
   while True:
    print("I Would like to get a: ")
    qwe = input()
    if qwe in lsa:
     print(qwe)
    elif qwe in fds:
        print(qwe)
    elif qwe in shot:
        print(qwe)
    elif qwe in mtms:
        print(qwe)
    else:
        print("There is no such thing like that ")
        continue

    dmi = int(input("How Many Servings Would you Like: "))
    laht.append(qwe)
    laht.append(dmi)
    print("So " + pngln, "you Like a " + str(laht[:2]))
    print (dmi, "Serves of: " + str(laht[:2]))
    break
cstmrinfo(nname)
kuha_order()
pnglhtn()

Answer 1

在 python 的 if...else 语句中使用逻辑“或”运算符时，您必须重复变量和值（我知道这听起来令人困惑，所以请看示例）

这意味着这不起作用：

if order == "Milktea" or "milktea":

正确的编队应该是：

if (order == "Milktea") or (order == "milktea"):

或者，如果您只想根据一系列值检查一个变量，请查看 match...case 语句 python 3.10+： https://learnpython.com/blog/python-match-case-statement/

################################################# ####

删除 mmu 行中的 if 顺序并缩进对应的 else（代码如下）

def kuha_order():
while True:
    order = input()
    print(order)
    if order == "Milktea":
        print(flvrs)
        laht.append(order)
        break
    elif order == "Foods":
        print(pgkn)
        laht.append(order)
        break
    elif order == "Drinks":
        print(shot)
        laht.append(order)
        break
    elif order == "Dessert":
        print(mtms)
        laht.append(order)
        break
    else:
        print("Sorry you input a thing that is not available on our menu")
        continue

你可以把它和我上面的答案结合起来得到你需要的东西:)

Answer 2

您可以使用lower() 或upper()。 请检查以下答案：

 if order.lower()=="milktea":
       print(flvrs)
       laht.append(order)
       break

或者

 if order.upper()=="MILKTEA":
       print(flvrs)
       laht.append(order)
       break