[英]JOLT shift transformation: filter by inner value of a property (not the name)
[英]JOLT shift transformation: filter by the value of the property (not the name)
我正在尝试使用 Jolt 转换来转换 JSON,在此处寻找一些输入。 我正在尝试按属性的值进行过滤。
我的目标是获得一个仅包含具有“删除”操作的项目的数组。
这是我的输入和预期的 output:
输入:
{
"id": 11,
"item": [
{
"id": "11_1",
"action": "add",
"item": [
{
"id": "11_1_1",
"action": "add",
"item": [
{
"id": "11_1_1_1",
"action": "remove"
}
]
},
{
"id": "11_1_2",
"action": "remove",
"item": [
{
"id": "11_1_2_1",
"action": "remove"
}
]
}
]
}
]
}
预期 output :
[
{
"id": "11_1_1_1",
"action": "remove"
},
{
"id": "11_1_2",
"action": "remove"
},
{
"id": "11_1_2_1",
"action": "remove"
}
]
你能帮我写一个简单的规范来做到这一点吗?
让我们通过在第一个规范中遍历树时确定案例是"item"
与else case("*")
来展平 JSON
和 label 个人 arrays 由他们的action
名称
然后选择remove
数组的对象最后一个规范
[
{
"operation": "shift",
"spec": {
"item": {
"*": {
"item": {
"*": {
"item": {
"*": {
"*": "@(1,id)[&1].&"
}
},
"*": "j[&1].&"
}
},
"*": "i[&1].&"
}
}
}
},
{
"operation": "shift",
"spec": {
"*": {
"*": "@(0,action)"
}
}
},
{
"operation": "shift",
"spec": {
"remove": {
"*": ""
}
}
}
]
jolt( http://jolt-demo.appspot.com/ )在操场上的演示是
您可以考虑另一个库Josson ,一个简单的语句就可以完成这项工作。 function 甚至支持未知和无限数量的路径级别。
https://github.com/octomix/josson
反序列化
Josson josson = Josson.fromJsonString(
"{" +
" \"id\": 11," +
" \"item\": [" +
" {" +
" \"id\": \"11_1\"," +
" \"action\": \"add\"," +
" \"item\": [" +
" {" +
" \"id\": \"11_1_1\"," +
" \"action\": \"add\"," +
" \"item\": [" +
" {" +
" \"id\": \"11_1_1_1\"," +
" \"action\": \"remove\"" +
" }" +
" ]" +
" }," +
" {" +
" \"id\": \"11_1_2\"," +
" \"action\": \"remove\"," +
" \"item\": [" +
" {" +
" \"id\": \"11_1_2_1\"," +
" \"action\": \"remove\"" +
" }" +
" ]" +
" }" +
" ]" +
" }" +
" ]" +
"}");
转型
JsonNode node = josson.getNode(
"cumulateCollect(item[action='remove']*.field(item:), item).flatten(1)");
System.out.println(node.toPrettyString());
Output
[ {
"id" : "11_1_2",
"action" : "remove"
}, {
"id" : "11_1_1_1",
"action" : "remove"
}, {
"id" : "11_1_2_1",
"action" : "remove"
} ]
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