[英]JOLT shift transformation: filter by inner value of a property (not the name)
[英]JOLT shift transformation: filter by inner value of a property (not the name) - only some properties
我正在尝试使用 Jolt 转换来转换 JSON 以在此处寻找一些输入。 我正在尝试按属性的内部值进行过滤。
我的目标是获得一个仅包含类型名称为“xx”的项目的数组。 但不是所有的item object,只有部分字段
{
"id": "11_1",
"action": "add",
"payment": {
"paied": true,
"coin": "dollar"
},
"type": {
"id": "11_1_xx",
"typeName": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
}
}
}
这是我的输入和预期的 output:
输入:
{
"id": 11,
"item": [
{
"id": "11_1",
"action": "add",
"payment": {
"paied": true,
"coin": "dollar"
},
"type": {
"id": "11_1_xx",
"typeName": "xx",
"typeGroup": "xx",
"typeValue": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
},
"reason": {
"id": "123",
"name": "xx"
}
},
"item": [
{
"id": "11_1_1",
"action": "add",
"payment": {
"paied": true,
"coin": "dollar"
},
"type": {
"id": "11_1_1_zz",
"typeName": "zz",
"typeGroup": "zz",
"typeValue": "zz"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
},
"reason": {
"id": "123",
"name": "xx"
}
},
"item": [
{
"id": "11_1_1_1",
"action": "add",
"payment": {
"paied": true,
"coin": "NIS"
},
"type": {
"id": "11_1_1_1_xx",
"typeName": "xx",
"typeGroup": "xx",
"typeValue": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
},
"reason": {
"id": "123",
"name": "xx"
}
}
}
]
},
{
"id": "11_1_2",
"action": "add",
"payment": {
"paied": false,
"coin": "dollar"
},
"type": {
"id": "11_1_2_xx",
"typeName": "xx",
"typeGroup": "xx",
"typeValue": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
},
"reason": {
"id": "123",
"name": "xx"
}
},
"item": [
{
"id": "11_1_2_1",
"action": "add",
"payment": {
"paied": false,
"coin": "NIS"
},
"type": {
"id": "11_1_2_1_zz",
"typeName": "zz",
"typeGroup": "zz",
"typeValue": "zz"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
},
"reason": {
"id": "123",
"name": "xx"
}
}
}
]
}
]
}
]
}
预计 output :
[
{
"id": "11_1",
"action": "add",
"payment": {
"paied": true,
"coin": "dollar"
},
"type": {
"id": "11_1_xx",
"typeName": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
}
}
},
{
"id": "11_1_1_1",
"action": "add",
"payment": {
"paied": true,
"coin": "NIS"
},
"type": {
"id": "11_1_1_1_xx",
"typeName": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
}
}
},
{
"id": "11_1_2",
"action": "add",
"payment": {
"paied": false,
"coin": "dollar"
},
"type": {
"id": "11_1_2_xx",
"typeName": "xx"
},
"details": {
"place": {
"id": "123",
"name": "xx"
},
"status": {
"id": "123",
"name": "xx"
}
}
}
]
你能帮我写一个简单的规范来做到这一点吗?
您可以使用以下解释的规范
[
{
// Determine all key-value pairs partitioned under the main value and type.typeValue combinations
"operation": "shift",
"spec": {
"item": {
"*": {
"item": {
"*": {
"item": {
"*": {
"type": {
"@(1,id)": "@(2,id).@(1,typeName).id", //traverse } character twice in order to reach the main id of the object
"@(1,action)": "@(2,id).@(1,typeName).action",
"*": "@(2,id).@(1,typeName).&1.&" // &1 replicates "type" key, & does the leaf value
},
"*": "@(1,id).@(1,type.typeName).&"
}
},
"type": {
"@(1,id)": "@(2,id).@(1,typeName).id",
"@(1,action)": "@(2,id).@(1,typeName).action",
"*": "@(2,id).@(1,typeName).&1.&"
},
"*": "@(1,id).@(1,type.typeName).&"
}
},
"type": {
"@(1,id)": "@(2,id).@(1,typeName).id",
"@(1,action)": "@(2,id).@(1,typeName).action",
"*": "@(2,id).@(1,typeName).&1.&"
},
"*": "@(1,id).@(1,type.typeName).&"
}
}
}
},
{
// Filter out by the desired value(in this case it's "xx")
"operation": "shift",
"spec": {
"*": {
"xx": ""
}
}
},
{
// Get rid of same repeating components of id and action arrays
"operation": "cardinality",
"spec": {
"*": {
"id": "ONE",
"action": "ONE"
}
}
},
{
// Get rid of undesired attributes
"operation": "remove",
"spec": {
"*": {
"type": {
"typeGroup": "",
"typeValue": ""
},
"det*": {
"reason": ""
}
}
}
}
]
您可以尝试图书馆Josson 。 Function map()
构建一个新的 ObjectNode。 Function field()
修改当前ObjectNode,可用于移除字段。 转换语句简短易懂。
https://github.com/octomix/josson
Josson josson = Josson.fromJsonString(inputJSON);
JsonNode node = josson.getNode(
"cumulateCollect(" +
" [type.typeName='xx']" + // filter
" .field(type.map(id, typeName)" + // need "type.id" and "type.typeName"
" ,details.field(reason:)" + // remove "details.reason"
" ,item:)" + // remove "item"
" ,item)"); // next round
System.out.println(node.toPrettyString());
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.