select 行的值与第二个表中的两列之一匹配：

Question

我有一张看起来像这样的桌子。

id        name
1         firstName
2         secondName
3         thirdName
4         fourthName

我想保留名称出现在第二个表中的“testName”或“prodName”列中的所有行，如下所示：

testName        prodName            coordinates
firstName       EN                  124
random          secondName          1244
thirdName       DE                  689
FifthName       DE                  457

我想要一个如下所示的结果表：

id        name                coordinates
1         firstName           124
2         secondName          1244
3         thirdName           689

如果我只与 table2 中的另一列进行比较，这样的事情就有效：

(select * 
  from `table1`
  where exists 
    (select 1
      from `table2` where testName = `table1`.name ));

但这会引发错误：

(select * 
  from `table1`
  where exists 
    (select 1
      from `table2` where testName = `table1`.name OR prodName = `table1`.name ));

LEFT SEMI JOIN cannot be used without a condition that is an equality of fields from both sides of the join.

Answer 1

请试试这个：

SELECT 
A.id
,A.name
,B.coordinates

FROM table1 A
INNER JOIN table2 B
ON A.name=B.testName OR A.name=B.prodName

Answer 2

您告诉过您还需要字段coordinate ，这在 table2 中不是唯一的。 这里是一个获取coordinate最大值的例子。 数据库中没有第一个条目，只有另一列中第一个日期的值等。您没有指定！

With table1 as 
(Select row_number() over() as id, * from unnest(["firstName","secondName","thirdName","fourthName"]) name
),table2 as 
(select * from
(select "firstName" as testname, "NB" as prodName
union all select "BG","secondName") ,
unnest(generate_array(1,1)) as coordinates
)
SELECT 
A.id
,A.name
,max(B.coordinates),
max(C.coordinates) as C_coordinates,
avg(ifnull(B.coordinates,C.coordinates)) as coordinate_new,

FROM table1 A
left JOIN table2 B
ON A.name=B.testName 
left JOIN table2 C
ON A.name=C.prodName
group by 1,2
having coordinate_new is not null

以下是使用Where过滤器的示例：

With table1 as 
(Select row_number() over() as id, * from unnest(["firstName","secondName","thirdName","fourthName"]) name
),table2 as 
(select "firstName" as testname, "NB" as prodName
union all select "BG","secondName") 

select * 
  from `table1`
  where exists 
    (select 1 from `table2` where testName = `table1`.name
    union all Select 1 from table2 where prodName = `table1`.name )

Answer 3

create temp table t1 as(
 select "firstName" as  testName ,"EN" as prodName , 124 as coordinates union all
 select "random","secondName",1244 union all
 select "thirdName","DE",689 union all
 select "FifthName","DE",457
);
 
create temp table t2 as(
select 1 as id,"firstName" as name,124 as coordinates union all
select 2,"secondName",1244 union all
select 3,"thirdName",689
);
 
 
create temp table t3 as(
select a.id as id,a.name as name from  t2 as a where a.id<=0 or exists (select coordinates from t1 as b1 where a.name = b1.testName or a.name=b1.prodName)
);
 
select t3.id,t3.name,t2.coordinates from t3 inner join t2 on t3.name=t2.name;

查询基于您在问题中提供的任何数据。 如果这不满足您的要求，请编辑问题并添加更多详细信息，并输入您要求的示例输入 output 数据。