如果前一个打印值与新值相同，如何在 python 中打印上一行？

Question

我运行了一个无限循环，它在控制台中不断打印几乎相同的内容。 为了可读性，如果它与上一个循环的内容相同，我不希望 python 打印到下一行

while True:
    print("The same line again. Lets overwrite")
    if random.randint(1, 1000) == 999:
        print("It is a different line. I do not want to overwrite")

Answer 1

跟踪最后打印的东西，在打印前检查它是否相等。

import random


class NewPrinter:
    def __init__(self):
        self.lastPrint = None

    def print(self, string):
        if string != self.lastPrint:
            print(string)
            self.lastPrint = string

np = NewPrinter()

while True:
    np.print("The same line again. Lets overwrite")
    if random.randint(1, 1000) == 999:
        np.print("It is a different line. I do not want to overwrite")

Answer 2

使用此代码，您将设置一个字符串“new_string”为其应打印的值，之后您将检查该值是否等于前一个值，如果不相等，则它将字符串设置为 new_string 并打印它.

string = "The same line again. Lets overwrite"
while True:
    if random.randint(1, 1000) == 999:
        new_string = "It is a different line. I do not want to overwrite"
    else:
        new_string = "The same line again. Lets overwrite"

    if string != new_string:
        string = new_string
        print(string)