C＃选择随机字符串

Question

我基本上只是想在字符串中选择一个随机值，并用“ |”分隔。 我找不到一个好的例子，有人有想法吗？

string[] mystrings = ("apple|orange|mayo|fruit|dog"):

string blah = "here i am "+resultsofrandom+" result chosen from mystring was " resultofrandom

显然，字符串等等只是一个例子，我只想从mystrings中随机选择一个字符串，然后重新转换为新字符串...

Answer 1

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');
Random rnd = new Random();
string blah1 = mystrings[rnd.Next(mystrings.Length)];
string blah2 = mystrings[rnd.Next(mystrings.Length)];
string sentence = "here i am " + blah1 + " result chosen from mystring was " + blah2 

Answer 2

您可以通过拆分字符串来完成此操作：

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');

然后使用Random类选择以下字符串之一：

int choice = new Random().Next(mystrings.Length);

现在，您可以将其放在一起：

string blah = "Your selection is: " + mystrings[choice];

Answer 3

Random rnd= new Random();
        int baseZeroArrayLen = 0;
        string[] mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
        baseZeroArrayLen = mystrings.Length - 1; 
        int randomNumber = rnd.Next(baseZeroArrayLen);
        string rndString = mystrings[randomNumber];

Answer 4

var mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
string blah = "here i am " + mystrings[new Random().Next(0, mystrings.Length)] + " result chosen..";

我认为它将按预期工作

Answer 5

应该这样做：

string[] mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
        Random randomInt = new Random();
            string blah = mystrings[randomInt.Next(mystrings.Length)];

Answer 6

使用String.Split()分割定界的字符串，并将每个单独的值存储在字符串数组中。 然后随机选择该数组的索引并显示相应的字符串。

Answer 7

完全不需要的LINQ替代方案。 虽然string.Format在这里可能不错。

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');

string blah = string.Format("here i am {0} result chosen from mystring was {0}",
               mystrings.Skip(new Random().Next(mystrings.Length)).First());