C＃選擇隨機字符串

Question

我基本上只是想在字符串中選擇一個隨機值，並用“ |”分隔。 我找不到一個好的例子，有人有想法嗎？

string[] mystrings = ("apple|orange|mayo|fruit|dog"):

string blah = "here i am "+resultsofrandom+" result chosen from mystring was " resultofrandom

顯然，字符串等等只是一個例子，我只想從mystrings中隨機選擇一個字符串，然后重新轉換為新字符串...

Answer 1

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');
Random rnd = new Random();
string blah1 = mystrings[rnd.Next(mystrings.Length)];
string blah2 = mystrings[rnd.Next(mystrings.Length)];
string sentence = "here i am " + blah1 + " result chosen from mystring was " + blah2 

Answer 2

您可以通過拆分字符串來完成此操作：

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');

然后使用Random類選擇以下字符串之一：

int choice = new Random().Next(mystrings.Length);

現在，您可以將其放在一起：

string blah = "Your selection is: " + mystrings[choice];

Answer 3

Random rnd= new Random();
        int baseZeroArrayLen = 0;
        string[] mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
        baseZeroArrayLen = mystrings.Length - 1; 
        int randomNumber = rnd.Next(baseZeroArrayLen);
        string rndString = mystrings[randomNumber];

Answer 4

var mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
string blah = "here i am " + mystrings[new Random().Next(0, mystrings.Length)] + " result chosen..";

我認為它將按預期工作

Answer 5

應該這樣做：

string[] mystrings = ("apple|orange|mayo|fruit|dog").Split('|');
        Random randomInt = new Random();
            string blah = mystrings[randomInt.Next(mystrings.Length)];

Answer 6

使用String.Split()分割定界的字符串，並將每個單獨的值存儲在字符串數組中。 然后隨機選擇該數組的索引並顯示相應的字符串。

Answer 7

完全不需要的LINQ替代方案。 雖然string.Format在這里可能不錯。

string[] mystrings = "apple|orange|mayo|fruit|dog".Split('|');

string blah = string.Format("here i am {0} result chosen from mystring was {0}",
               mystrings.Skip(new Random().Next(mystrings.Length)).First());