[英]How to get a complete exception stack trace in Python
以下片段:
import traceback
def a():
b()
def b():
try:
c()
except:
traceback.print_exc()
def c():
assert False
a()
产生这个输出:
Traceback (most recent call last):
File "test.py", line 8, in b
c()
File "test.py", line 13, in c
assert False
AssertionError
如果我想要完整的堆栈跟踪,包括对 a 的调用,我应该使用什么?
如果重要的话,我有 Python 2.6.6
编辑:如果我将 try 排除在外并让异常传播到顶层,我想要得到的信息与我得到的信息相同。 这个片段例如:
def a():
b()
def b():
c()
def c():
assert False
a()
产生这个输出:
Traceback (most recent call last):
File "test.py", line 10, in <module>
a()
File "test.py", line 2, in a
b()
File "test.py", line 5, in b
c()
File "test.py", line 8, in c
assert False
AssertionError
这是基于此答案的功能。 当不存在异常时,它也将起作用:
def full_stack():
import traceback, sys
exc = sys.exc_info()[0]
stack = traceback.extract_stack()[:-1] # last one would be full_stack()
if exc is not None: # i.e. an exception is present
del stack[-1] # remove call of full_stack, the printed exception
# will contain the caught exception caller instead
trc = 'Traceback (most recent call last):\n'
stackstr = trc + ''.join(traceback.format_list(stack))
if exc is not None:
stackstr += ' ' + traceback.format_exc().lstrip(trc)
return stackstr
print full_stack()
将打印到顶部的完整堆栈跟踪,包括例如IPython 的interactiveshell.py
调用,因为(据我所知)没有办法知道谁会捕获异常。 无论如何,这可能不值得弄清楚......
如果从一个except
块中调用print full_stack()
, full_stack
将包括一直到raise
的堆栈跟踪。 在标准 Python 解释器中,这将与您在未捕获异常时收到的消息相同(这就是为什么del stack[-1]
存在的原因,您不关心except
块而是关心try
块)。
我不知道是否有更好的方法,但这是我所做的:
import traceback
import sys
def format_exception(e):
exception_list = traceback.format_stack()
exception_list = exception_list[:-2]
exception_list.extend(traceback.format_tb(sys.exc_info()[2]))
exception_list.extend(traceback.format_exception_only(sys.exc_info()[0], sys.exc_info()[1]))
exception_str = "Traceback (most recent call last):\n"
exception_str += "".join(exception_list)
# Removing the last \n
exception_str = exception_str[:-1]
return exception_str
def main1():
main2()
def main2():
try:
main3()
except Exception as e:
print "Printing only the traceback above the current stack frame"
print "".join(traceback.format_exception(sys.exc_info()[0], sys.exc_info()[1], sys.exc_info()[2]))
print
print "Printing the full traceback as if we had not caught it here..."
print format_exception(e)
def main3():
raise Exception()
if __name__ == '__main__':
main1()
这是我得到的输出:
Printing only the traceback above the current stack frame
Traceback (most recent call last):
File "exc.py", line 22, in main2
main3()
File "exc.py", line 31, in main3
raise Exception()
Exception
Printing the full traceback as if we had not caught it here...
Traceback (most recent call last):
File "exc.py", line 34, in <module>
main1()
File "exc.py", line 18, in main1
main2()
File "exc.py", line 22, in main2
main3()
File "exc.py", line 31, in main3
raise Exception()
Exception
用
traceback.print_stack()
http://docs.python.org/library/traceback.html#traceback.print_stack
suxmac2 $ python out.py File "out.py", line 16, in <module> a() File "out.py", line 5, in a b() File "out.py", line 11, in b traceback.print_stack()
这是Tobias Kienzler answer 的一个更好的变体。 它的工作原理相同,但不能在except
块中调用,而是在更深的地方调用。 换句话说,这个变体将打印相同的堆栈,当调用时
try:
...
except Exception:
print full_stack()
或者
def print_full_stack():
print full_stack()
try:
...
except Exception:
print_full_stack()
这是代码:
def full_stack():
import traceback, sys
exc = sys.exc_info()[0]
if exc is not None:
f = sys.exc_info()[-1].tb_frame.f_back
stack = traceback.extract_stack(f)
else:
stack = traceback.extract_stack()[:-1] # last one would be full_stack()
trc = 'Traceback (most recent call last):\n'
stackstr = trc + ''.join(traceback.format_list(stack))
if exc is not None:
stackstr += ' ' + traceback.format_exc().lstrip(trc)
return stackstr
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