[英]remove values from a python dict
我有这样的python字典:
{'1' : {'1': {'A' : 34, 'B' : 23, 'C' : nan, 'D': inf, ...} ....} ....}
对于每个“字母”键,我必须计算一些内容,但是我获得了inf或nan等值,因此需要删除它们。 我该怎么办?
我的第一个尝试是“剪切”此类值,即仅返回0到1000之间的值,但是当我这样做时,我得到了一个带有空值的字典:
{'1' : {'1': {'A' : 34, 'B' : 23, 'C' : {}, 'D': {}, ...} ....} ....}
也许有更好的解决方案,请帮忙!!!!
这是我的代码的一部分,(Q和L是具有我需要计算的信息的其他字典):
for e in L.keys():
dR[e] = {}
for i in L[e].keys():
dR[e][i] = {}
for l, ivalue in L[e][i].iteritems():
for j in Q[e].keys():
dR[e][i][j] = {}
for q, jvalue in Q[e][j].iteritems():
deltaR = DeltaR(ivalue, jvalue) #this is a function that I create previously
if (0 < deltaR < 100):
dR[e][i][j] = deltaR
您应该能够使用del语句删除字典项。 例如:
del dct['1']['1']['C']
我在这里在黑暗中拍摄,但是您可能可以通过几种不同的方式进行拍摄。 一种方法是计算值,然后在将其粘贴到字典中之前确定是否要保留它。
d = {}
for letter in 'ABCDEFGHIJKLMNOPQRSTUVWXYZ':
# I don't actually know how you're calculating values
# and it kind of doesn't matter
value = calculate(letter)
if value in (inf, nan):
continue
d[letter] = value
我正在简化字典,以便仅注意实际上使用字母作为键的数据部分,因为您实际上没有给出任何上下文。 话虽如此,除非有理由不建议,否则我可能会接受第一个建议。
for e in L.keys():
dR[e] = {}
for i in L[e].keys():
dR[e][i] = {}
for l, ivalue in L[e][i].iteritems():
for j in Q[e].keys():
#dR[e][i][j] = {} # What's up with this? If you don't want an empty dict,
# just don't create one.
for q, jvalue in Q[e][j].iteritems():
deltaR = DeltaR(ivalue, jvalue) #this is a function that I create previously
if (0 < deltaR < 100):
dR[e][i][j] = deltaR
if dR[e][i][j] in (nan, inf):
del dR[e][i][j]
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