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[英]ios objects are released in Debug mode but not being released in Release mode
[英]iOS - Objects being released?
我有以下代码:
Dummy *dummy = [[Dymmy alloc] initWithDictionary:dummyData];
DummyTableItem *dummyTableItem = [DummyTableItem itemWithDummy: dummy];
[_data addObject: dummyTableItem];
初始化函数如下:
+ (id) itemWithDummy: (Dummy *) dummy {
DummyTableItem *item = [[[self alloc] init] autorelease];
item.dummy = dummy;
return item;
}
- (id) init {
self = [super init];
if( self ) {
dummy = nil;
}
return self;
}
假人声明为(非原子,保留)
和虚拟:
@synthesize name=_name;
- (id) initWithDictionary: (NSDictionary *) dictionary {
self = [super init];
if( self != nil ) {
if( [dictionary objectForKey:@"name"] )
_name = [dictionary objectForKey:@"name"];
}
return self;
}
名称再次声明为(非原子,保留)
当我稍后尝试访问dummyTableItem.dummy.name并将其设置为UILabel时,我收到“-[CFString isEqualToString:]:消息发送给已释放实例0x5b37a10”
我对保留的对象所做的事情完全错误吗? 我在这里想念什么? 同样在代码的第一部分中,在将其添加到_data(这是NSMutableArray吗?)之后,我应该释放dummyTableItem吗?
这应该可以解决Dummy的@implementation内部的问题:
@synthesize name=_name;
- (id) initWithDictionary: (NSDictionary *) dictionary {
self = [super init];
if (self) {
_name = [[dictionary objectForKey:@"name"] retain]; //retain it :)
}
return self;
}
由于您将name
声明为保留,因此您应该拥有该名称(这就是为什么我在分配名称时添加了retain
)。 此外,您不需要检查if( [dictionary objectForKey:@"name"] )
因为_name = [nil retain];
if( [dictionary objectForKey:@"name"] )
_name = [nil retain];
反正是nil
:)
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