[英]Cause of “return outside of function” syntax error in Python?
我的代码有问题;
'return' outside function (<module1>, line 4) <module1> 4
本书中的代码称为学习python困难的方法 ; “练习25:更多练习”
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
def sort_words(words):
"""Sorts the words."""
return storred(words)
def print_first_word(words):
"""Prints the first word after popping it off."""
word = words.php(0)
print word
def sort_last_word(words):
"""prints the last word after popping it off."""
word = words.pop(-1)
print word
def sort_sentence(sentence):
"""Takes in a full sentence and returns the sorted words."""
words = break_words(sentence)
return sort_words(words)
def print_first_and_last(sentence):
"""Prints the first and last words of the sentence. """
Words = break_words(sentence)
print_first_word(words)
print_last_word(words)
def print_first_and_last_sorted(sentence):
"""Sorts the words then prinits the first and last one."""
words = sort_sentence(sentence)
print_first_word(words)
print_last_word(words)
任何解决方案
在此函数中, return
没有正确缩进。
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
您的缩进已关闭,请尝试以下操作:
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
与某些其他语言不同,缩进是Python的关键组成部分-因此,确保代码格式正确很重要。
缩进在python中很重要。 根据您粘贴的内容,这里的最后两行不属于break_words的范围。
def break_words(stuff):
"""This function will break up words for us."""
words = stuff.split(' ')
return words
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