[英]Point around a square with javascript
AtomicRobot在stackoverflow上给了我下面的代码。
var x,y;
// amount of chairs
var totalChairs = 12;
// square size
var squareSize = 200;
var chairSize = 60;
// issues with 3,5,7,8,9,10,11
for(var i=0; i<totalChairs; i++){
var angle = 2*Math.PI * i/totalChairs;
if (angle > Math.PI/4 && angle <= Math.PI* 3/4){
x = (squareSize/2) / Math.tan(angle);
y = -squareSize/2 - chairSize/2;
} else if (angle > Math.PI* 3/4 && angle <= Math.PI* 5/4){
x = -squareSize/2 - chairSize/2;
y = (squareSize/2) * Math.tan(angle);
} else if (angle > Math.PI* 5/4 && angle <= Math.PI* 7/4){
x = -(squareSize/2) / Math.tan(angle);
y = -squareSize/2 + squareSize + chairSize/2;
} else {
x = -squareSize/2 + squareSize + chairSize/2;
y = -(squareSize/2) * Math.tan(angle);
}
x -= Math.round(chairSize/2) - squareSize/2;
y -= Math.round(chairSize/2) - squareSize/2;
$("#square").append("<div class='chair' style='left:"+x+"px;top:"+y+"px;'></div>");
}
这是使用javascript在桌子周围绘制椅子,它对于以下数量的椅子1,2,4,6,12非常有效,距离的绘制是相等的。
但是,随着以下椅子数量3、5、7、8、9、10、11的出现,似乎取决于椅子的宽度。
是他们的任何人都可以让我知道为什么可能会发生这种数学不是我的强项,并且真的希望对此有所帮助,您可以在这里看到一个有8个椅子的示例。
谢谢
我已经在彻底改变这一现状方面取得了进展,现在我实际上正在了解这一过程,并且可以扩展表格以适合某些人的还款问题????
var x,y;
// amount of chairs
var totalChairs = 18;
var chairSize = 60;
// square size
var squareSize = Math.round(totalChairs/4) * chairSize;
//alert("squareSize: " + squareSize);
// issues with 5,9,13,17,21
// works with 1,2,4,6,12
var remainder = Math.round(totalChairs/4);
var s1 = 0;
var s2 = 0;
var s3 = 0;
var s4 = 0;
for(var i=0; i<totalChairs; i++){
var iter = i;
if(iter+1 <= remainder){
var s1i = s1++;
console.log("s1i: " + s1i);
x = s1i * chairSize;
y = -chairSize;
newr = remainder*2;
} else if(iter+1 <= newr){
var s2i = s2++;
console.log("s2i: " + s2i);
y = s2i * chairSize;
x= squareSize;
newe = remainder*3;
} else if(iter+1 <= newe){
var s3i = s3++;
console.log("s3i: " + s3i);
x = - s3i * chairSize + squareSize - chairSize;
y = squareSize;
}else{
var s4i = s4++;
console.log("s4i: " + s4i);
y = - s4i * chairSize + squareSize - chairSize;
x= -chairSize;
}
$("#square").css({"width":(squareSize) + "px","height":(squareSize) + "px"});
$("#square").append("<div class='chair' style='left:"+Math.round(x)+"px;top:"+Math.round(y)+"px;'><p>"+i+"<br/>x"+x+",y"+y+"</p></div>");
$(".chair").css({"width":(chairSize) + "px","height":(chairSize) + "px"});
}
可以在这里查看jsfiddle版本http://jsfiddle.net/isimpledesign/Ld769/19/
我想弄清楚有多少需要适合4个方面之一。 4 * 2 = 8,不够,4 * 3 = 12 OK !,这意味着3面变为3面,而1变为2。这意味着最小宽度和高度必须与最密集的面相同(以便就位舒适地)
是否要均匀分开? 只需弄清楚椅子的数量,比如说11张,将其分成360个就可以算出您的分离角度,然后将其投影到正方形上
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