將.csv數據導入類

Question

我有一些代碼可以將類中的數據保存到.csv文件中，但是我不確定如何將其讀回到類中，因此可以將其放入列表視圖中。 這是保存的代碼：

        SaveFileDialog save = new SaveFileDialog();
        save.Filter = "Excel|*.csv";

        if (save.ShowDialog() == DialogResult.OK)
        {
            StreamWriter sw = new StreamWriter(save.FileName);
            try
            {
                sw.WriteLine("Name" + ";" + "Authors" + ";" + "Pages" + ";" + "Date" + ";" + "Price" + ";" + "Copies");
                foreach (Book b in bookList)
                {
                    string aux = "";
                    aux = string.Join(";", b.Authors);//I know I will probably need to change ';' here because it will have trouble reading it
                    sw.WriteLine(b.Name + ";" + aux + ";" + b.Pages + ";" + b.Date.ToString("dd.MM.yyyy") + ";" + b.Price + ";" + b.Copies);
                }
            }
            catch (IOException ert)
            {
                MessageBox.Show(ert.Message);
            }
            catch (Exception ew)
            {
                MessageBox.Show(ew.Message);
            }
            finally
            {
                sw.Close();
            }
        }

Answer 1

這實際上很容易。 假設您有以下課程Book ：

public class Book
{
    public string Name { get; set; }
    public int Pages { get; set; }
    public string AuthorName { get; set; }
}

然后，您可以像這樣簡單地閱讀它：

var BooksFromCsv = from row in File.ReadLines(@"C:\books.csv").Where(arg => !string.IsNullOrWhiteSpace(arg) && arg.Length > 0).AsEnumerable()
                   let column = row.Split(';')
                   select new Book
                   {
                      Name = column[0],
                      Pages = column[1],
                      AuthorName = column[2],
                   };

結果將是IEnumerable<Book> 。 如果要列表或數組，只需附加.ToList()或.ToArray() 。

Answer 2

如果只想永久保存數據，則可以對對象進行序列化和反序列化，如下所示：

// 救

using (var fs = new FileStream(path, FileMode.Create))
{
      var xSer = new XmlSerializer(typeof(objecttype));
      xSer.Serialize(fs, myObject);
}

//加載

using (var fs = new FileStream(path, FileMode.Open))
{
     var xSer = new XmlSerializer(typeof(objecttype));
     myObject = (objecttype)xSer.Deserialize(fs);
}