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[英]Calculate the time difference between two hh:mm columns in a pandas dataframe
[英]Calculate Time Difference Between Two Pandas Columns in Hours and Minutes
我在數據todate
有兩列fromdate
和todate
。
import pandas as pd
data = {'todate': [pd.Timestamp('2014-01-24 13:03:12.050000'), pd.Timestamp('2014-01-27 11:57:18.240000'), pd.Timestamp('2014-01-23 10:07:47.660000')],
'fromdate': [pd.Timestamp('2014-01-26 23:41:21.870000'), pd.Timestamp('2014-01-27 15:38:22.540000'), pd.Timestamp('2014-01-23 18:50:41.420000')]}
df = pd.DataFrame(data)
我添加了一個新列diff
,以使用以下方法查找兩個日期之間的差異
df['diff'] = df['fromdate'] - df['todate']
我得到diff
列,但它包含days
,當超過 24 小時時。
todate fromdate diff
0 2014-01-24 13:03:12.050 2014-01-26 23:41:21.870 2 days 10:38:09.820000
1 2014-01-27 11:57:18.240 2014-01-27 15:38:22.540 0 days 03:41:04.300000
2 2014-01-23 10:07:47.660 2014-01-23 18:50:41.420 0 days 08:42:53.760000
如何將我的結果僅轉換為小時和分鍾(即天轉換為小時)?
Pandas 時間戳差異返回一個 datetime.timedelta 對象。 這可以通過使用 *as_type* 方法輕松轉換為小時,如下所示
import pandas
df = pandas.DataFrame(columns=['to','fr','ans'])
df.to = [pandas.Timestamp('2014-01-24 13:03:12.050000'), pandas.Timestamp('2014-01-27 11:57:18.240000'), pandas.Timestamp('2014-01-23 10:07:47.660000')]
df.fr = [pandas.Timestamp('2014-01-26 23:41:21.870000'), pandas.Timestamp('2014-01-27 15:38:22.540000'), pandas.Timestamp('2014-01-23 18:50:41.420000')]
(df.fr-df.to).astype('timedelta64[h]')
屈服,
0 58
1 3
2 8
dtype: float64
這讓我.astype()
因為上面的.astype()
解決方案對我不起作用。 但我找到了另一種方法。 沒有計時或任何東西,但可能對其他人有用:
t1 = pd.to_datetime('1/1/2015 01:00')
t2 = pd.to_datetime('1/1/2015 03:30')
print pd.Timedelta(t2 - t1).seconds / 3600.0
...如果你想要幾個小時。 要么:
print pd.Timedelta(t2 - t1).seconds / 60.0
...如果你想要幾分鍾。
更新:這里曾經有一條有用的評論提到使用.total_seconds()
跨越多天的時間段。 既然它不見了,我已經更新了答案。
days + hours
。 分鍾不包括在內。hh:mm
或x hours y minutes
,需要額外的計算和字符串格式。timedelta
數學將總小時數或總分鍾數作為浮點數timedelta
,並且比使用.astype('timedelta64[h]')
更快timedelta
objects :請參閱支持的操作。datetime64[ns] dtype
。 需要使用pandas.to_datetime()
轉換所有相關列。import pandas as pd
# test data from OP, with values already in a datetime format
data = {'to_date': [pd.Timestamp('2014-01-24 13:03:12.050000'), pd.Timestamp('2014-01-27 11:57:18.240000'), pd.Timestamp('2014-01-23 10:07:47.660000')],
'from_date': [pd.Timestamp('2014-01-26 23:41:21.870000'), pd.Timestamp('2014-01-27 15:38:22.540000'), pd.Timestamp('2014-01-23 18:50:41.420000')]}
# test dataframe; the columns must be in a datetime format; use pandas.to_datetime if needed
df = pd.DataFrame(data)
# add a timedelta column if wanted. It's added here for information only
# df['time_delta_with_sub'] = df.from_date.sub(df.to_date) # also works
df['time_delta'] = (df.from_date - df.to_date)
# create a column with timedelta as total hours, as a float type
df['tot_hour_diff'] = (df.from_date - df.to_date) / pd.Timedelta(hours=1)
# create a colume with timedelta as total minutes, as a float type
df['tot_mins_diff'] = (df.from_date - df.to_date) / pd.Timedelta(minutes=1)
# display(df)
to_date from_date time_delta tot_hour_diff tot_mins_diff
0 2014-01-24 13:03:12.050 2014-01-26 23:41:21.870 2 days 10:38:09.820000 58.636061 3518.163667
1 2014-01-27 11:57:18.240 2014-01-27 15:38:22.540 0 days 03:41:04.300000 3.684528 221.071667
2 2014-01-23 10:07:47.660 2014-01-23 18:50:41.420 0 days 08:42:53.760000 8.714933 522.896000
.total_seconds()
是在核心開發人員休假時添加和合並的,並且不會被批准。
.total_xx
方法的原因。# convert the entire timedelta to seconds
# this is the same as td / timedelta(seconds=1)
(df.from_date - df.to_date).dt.total_seconds()
[out]:
0 211089.82
1 13264.30
2 31373.76
dtype: float64
# get the number of days
(df.from_date - df.to_date).dt.days
[out]:
0 2
1 0
2 0
dtype: int64
# get the seconds for hours + minutes + seconds, but not days
# note the difference from total_seconds
(df.from_date - df.to_date).dt.seconds
[out]:
0 38289
1 13264
2 31373
dtype: int64
dateutil
維護人員的dateutil
:
(df.from_date - df.to_date) / pd.Timedelta(hours=1)
(df.from_date - df.to_date).dt.total_seconds() / 3600
dateutil
模塊為標准datetime
模塊提供了強大的擴展。%%timeit
測試import pandas as pd
# dataframe with 2M rows
data = {'to_date': [pd.Timestamp('2014-01-24 13:03:12.050000'), pd.Timestamp('2014-01-27 11:57:18.240000')], 'from_date': [pd.Timestamp('2014-01-26 23:41:21.870000'), pd.Timestamp('2014-01-27 15:38:22.540000')]}
df = pd.DataFrame(data)
df = pd.concat([df] * 1000000).reset_index(drop=True)
%%timeit
(df.from_date - df.to_date) / pd.Timedelta(hours=1)
[out]:
43.1 ms ± 1.05 ms per loop (mean ± std. dev. of 7 runs, 10 loops each)
%%timeit
(df.from_date - df.to_date).astype('timedelta64[h]')
[out]:
59.8 ms ± 1.29 ms per loop (mean ± std. dev. of 7 runs, 10 loops each)
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