[英]Showing angles around plot in matlab / octave
我可以用pol2cart創建一個圖,但是如何使角度顯示在線條的末端? 參見下面的代碼:
hold on ;
for angle = 0:20:(360-20)
[x1,y1] = pol2cart( angle / 180 * pi , [0 2]);
plot(x1,y1,'r')
end
for rho = 0:0.1:2
[x1,y1] = pol2cart( 0:0.01:2*pi , rho);
plot(x1,y1,'b')
end
axis equal
我正在嘗試使角度增量顯示在周圍,請參見下圖。 請注意,我並沒有繪制所有編號的角度,只是第一對夫婦就說明了我要做什么
PS:我使用的是八度3.8.1,它嘗試使用與matlab相同的語言語法
你可以做類似的事情
step = 20;
r= 2.2;
for idx = 0:step:360-step
text(r*cos(pi*idx/180),r*sin(pi*idx/180),num2str(idx), ...
'HorizontalAlignment','center', 'color',[1 .5 0])
end
為了更好地適合,請包括
axis(1.05*[-r r -r r])
axis equal
(這適用於MATLAB,我不知道語法在Octave中是否完全相同。)
這是動畫的信息和情節
%polar_chart_with_angles and there opposites
clear all, clc, clf
%find how many angles to make one full cycleremeber to divide by two if using stereo signal 180 out of phase
incr=72;
angle_wanted=incr;
n = lcm(360, 180 - angle_wanted) / (180 - angle_wanted)
angle_div=[0:incr:incr*n] %angle divsions
angle_div_mod=mod(angle_div,360) %angle divsions mod into 360
angle_div_mod_opp=mod(angle_div+180,360) %oppsite angle divsions mod into 360
%for circles
r= 2.2;
for rho = 0:0.1:2
[x1,y1] = pol2cart( 0:0.01:2*pi , rho);
plot(x1,y1,'b')
axis(1.10*[-r r -r r])
axis equal
hold on;
end
%for orig angles
for ii=1:n
angle=angle_div(ii)
[x1,y1] = pol2cart( angle / 180 * pi , [0 2]);
plot(x1,y1,'r')
hold on;
title_h=title(['Norig= ', int2str(ii)]);
%title_h = title('This is the title');
set(title_h, 'Position', [0.5, 0.02],'VerticalAlignment', 'bottom', 'HorizontalAlignment', 'left')
%%for creating orig angles
idx=angle_div_mod(ii);
text(r*cos(pi*idx/180),r*sin(pi*idx/180),num2str(idx), 'HorizontalAlignment','center', 'color',[1 .5 0])
pause (.1)
end
%for oppsite angles
for ii=1:n
angle_opp=angle_div_mod_opp(ii)
[x1,y1] = pol2cart( angle_opp/ 180 * pi , [0 2]);
plot(x1,y1,'g')
hold on;
title(['Nopp= ', int2str(ii)]);
%for creating oppsite angles
idx=angle_div_mod_opp(ii);
text(r*cos(pi*idx/180),r*sin(pi*idx/180),num2str(idx), 'HorizontalAlignment','center', 'color',[.5 .7 .7])
pause (.1)
end
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