為什么會出現錯誤“ exceptions.ValueError：太多值無法解包”？

Question

我有以下字典，即從XHR請求生成的json對象，其中字典鍵由元組組成：

{(u'goal', u'corner', u'rightfoot'): 1, (u'goal', u'openplay', u'rightfoot'): 3, (u'miss', 
    u'corner', u'header'): 8, (u'goal', u'corner', u'header'): 1, (u'goal', u'openplay', u'leftfoot'): 2,
     (u'miss', u'openplay', u'rightfoot'): 30, (u'miss', u'corner', u'rightfoot'): 2, (u'miss', 
    u'crossedfreekick', u'header'): 3, (u'goal', u'penalty', u'rightfoot'): 1, (u'miss', u'fastbreak', 
    u'rightfoot'): 2, (u'miss', u'crossedfreekick', u'rightfoot'): 3, (u'goal', u'openplay', u'header'): 
    1, (u'goal', u'crossedfreekick', u'rightfoot'): 1, (u'miss', u'openplay', u'header'): 2, (u'goal', 
    u'crossedfreekick', u'header'): 1, (u'miss', u'openplay', u'leftfoot'): 22, (u'miss', 
    u'directfreekick', u'rightfoot'): 1, (u'miss', u'crossedfreekick', u'leftfoot'): 1}

我正在使用以下代碼來有條件地求和以上字典中的值：

goal1 = {"'goal','openplay','leftfoot'", "'goal','openplay','rightfoot'", "'goal','openplay','header'", "'goal','openplay','otherbodypart'"}
                            regex1 = sum(int(value) for key, value in regex if key in goal1)

但是，這會產生以下錯誤消息：

regex1 = sum(int(value) for key, value in regex if key in goal1)
    exceptions.ValueError: too many values to unpack

誰能向我解釋這是為什么和/或更正替代語法？

謝謝

Answer 1

regex1 = sum(int(value) for key, value in regex.items() if key in goal1)

您需要使用包含鍵和值的dict.items ，循環遍歷regex ，僅對鍵進行迭代，因此無法解壓鍵和值，從而導致錯誤。

這些鍵也是元組，因此您需要將這些鍵作為元組存儲在goal1 ：

goal1 = {('goal','openplay','leftfoot'), ('goal','openplay','rightfoot'), ('goal','openplay','header'), ('goal','openplay','otherbodypart')}


print(regex1)
6