嗨，嘗試根據數組值打印一定數量的字符。 Java的

Question

所以我的問題是如何根據數組值打印一定數量的字符？

所以目前我有一個這樣全局聲明的數組

static float timesOccured [] = {5,3,7,3,1};

在一種名為draw的方法中，我嘗試了一些嘗試來獲取它，因此輸出將像這樣

|||||

|||

|||||||

|||

|

有人可以幫我嗎？ 非常感激。

Answer 1

您將需要使用嵌套的for循環，如下所示：

for (int i = 0; i < timesOccured.length; i++) {
     for (int j = 0; j < timesOccured[i]; j++) {
        // print characters here
     }
}

遍歷timesOccured數組並獲取每個條目； 並使用條目（即timesOccured[i] ）在嵌套的for循環中打印行。

我希望這有幫助。

Answer 2

public class PrintChar {

static float timesOccured [] = {5,3,7,3,1};

public static void draw(){

    for(int i=0; i<timesOccured.length;i++){

        for(int j=0; j< timesOccured[i]; j++){
            System.out.print("!");
        }

        System.out.println();
    }
}

public static void main(String[] args) {
    draw();
}

}

Answer 3

這有七種方法：

import org.apache.commons.lang.StringUtils;
import com.google.common.base.Strings;

public class StringRepeat {
  static int timesOccured[] = { 5, 3, 7, 3, 1 };
  static String s = "|";
  static String t = "||||||||||||||||||";

  public static String repeat(int j) {
    return (t.substring(0, j));
  }

  public static void main(String[] args) {

    System.out.println("Using native Java String.substring");
    for (int i = 0; i < timesOccured.length; i++) {
      System.out.println(repeat(timesOccured[i]));
    }

    System.out.println("\nUsing native Java char.replace");
    for (int i = 0; i < timesOccured.length; i++) {
      System.out.println(new String(new char[timesOccured[i]]).replace("\0", s));
    }

    System.out.println("\nUsing native Java String.format.replace");
    String result = "";
    for (int i = 0; i < timesOccured.length; i++) {
      System.out.println(String.format(String.format("%%0%dd", timesOccured[i]), 0).replace("0",s));
    } 
    System.out.println(result);

    System.out.println("\nUsing native Java StringBuilder.append");
    for (int i = 0; i < timesOccured.length; i++) {
      StringBuilder sb = new StringBuilder();
      for (int j = 0; j < timesOccured[i]; j++) { sb.append(s); };
      System.out.println(sb.toString());
    }

    System.out.println("\nUsing native Jave double for loops");
    for (int i = 0; i < timesOccured.length; i++) {
      String u = "";
      for (int j = 0; j < timesOccured[i]; j++) {
        u = u + s;
      }
      System.out.println(u);
    }

    System.out.println("\nUsing org.apache.commons.lang.StringUtils.repeat");
    for (int i = 0; i < timesOccured.length; i++) {
      System.out.println(StringUtils.repeat(s, timesOccured[i]));
    }

    System.out.println("\nUsing com.google.common.base.Strings.repeat");
    for (int i = 0; i < timesOccured.length; i++) {
      System.out.println(Strings.repeat(s, timesOccured[i]));
    }

  }
}