匹配和追加

Question

我試圖弄清楚如何通過另一個列表來運行一個列表，並且每當名字匹配時，將其追加到新列表（如果存在）

list1 = [["Ryan","10"],["James","40"],["John","30"],["Jake","15"],["Adam","20"]]

list2 = [["Ryan","Canada"],["John","United States"],["Jake","Spain"]]

所以看起來像這樣。

list3 = [["Ryan","Canada","10"],["John","United States","30"],["Jake","Spain","15"]

到目前為止，我還沒有真正能夠做到，因此即使是最小的指導也將不勝感激。 謝謝。

Answer 1

您可以將它們轉換為字典，然后使用列表理解：

dic1 = dict(list1)
dic2 = dict(list2)
list3 = [[k,dic2[k],dic1[k]] for k in dic2 if k in dic1]

Answer 2

如果不關心排序，則最直接的方法是將列表轉換成更合適的數據結構：字典。

ages      = dict(list1)
countries = dict(list2)

這將使組合數據變得很困難：

>>> {name: [ages[name], countries[name]] for name in ages.keys() & countries.keys()}
{'Ryan': ['10', 'Canada'], 'Jake': ['15', 'Spain'], 'John': ['30', 'United States']}

甚至更好，使用嵌套字典：

>>> {name: {'age': ages[name], 'country': countries[name]} for name in ages.keys() & countries.keys()}
{'Ryan': {'country': 'Canada',        'age': '10'},
 'Jake': {'country': 'Spain',         'age': '15'},
 'John': {'country': 'United States', 'age': '30'}}

Answer 3

如果名稱是唯一的，則可以將list1放入字典中，然后遍歷list2添加該字典中的項目。

list1 = [["Ryan","10"],["James","40"],["John","30"],["Jake","15"],["Adam","20"]]
list2 = [["Ryan","Canada"],["John","United States"],["Jake","Spain"]]
list1_dict = dict(list1)
output = [item + [list1_dict[item[0]]] for item in list2]

如果不是，那么您需要決定如何處理重復名稱的情況。

Answer 4

您可以使用set和OrderedDict來組合通用名稱並保持順序：

list1 = [["Ryan","10"],["James","40"],["John","30"],["Jake","15"],["Adam","20"]]

list2 = [["Ryan","Canada"],["John","United States"],["Jake","Spain"]]


from collections import OrderedDict

# get set of names from list2
names = set(name for name,_ in list2)

# create an OrderedDict using name as key and full sublist as value
# filtering out names that are not also in list2
d = OrderedDict((sub[0], sub) for sub in list1 if sub[0] in names)

for name, country in list2:
     if name in d:
         # add country from  each sublist with common name
         d[name].append(country)

print(d.values()) # list(d.values()) for python3
[['Ryan', '10', 'Canada'], ['John', '30', 'United States'], ['Jake', '15', 'Spain']]

如果list2始終具有公用名，則可以if name in d:刪除if name in d: