我如何從python運行命令行

Question

我在終端中運行以下命令：

mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv

我嘗試使用以下命令運行它：

>>> import subprocess
>>> subprocess.call(["mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv"])

我收到以下錯誤：

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 524, in call
return Popen(*popenargs, **kwargs).wait()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 711, in __init__
errread, errwrite)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1308, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory

Answer 1

最好的方法是將命令分解為單獨的“單詞”：

>>> subprocess.call(["mongoexport", "--db", "database_name", "--collection", "agents", "--type=csv", "--fieldFile", "agFieldsTest.txt", "--out", "file/path/agTestInfo.csv"])

另外，您可以使用shell=True讓shell為您執行此操作：

>>> subprocess.call(["mongoexport --db database_name --collection agents --type=csv --fieldFile agFieldsTest.txt --out file/path/agTestInfo.csv"], shell=True)