井字游戲：如何循環播放？

Question

目前正在制作Tic Tac Toe Game的游戲遇到了一個問題，即在玩家獲勝后循環使用該功能。 我嘗試使用exit(1); 但是，這只是退出整個程序，並且不允許循環。 我想要退出游戲，然后用是/否問題提示用戶是否循環游戲。 該函數的外觀如下。

void checkwin(char drawTable[]){

if(drawTable[0] == 'X' && drawTable[1] == 'X' && drawTable[2] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}

else if(drawTable[3] == 'X' && drawTable[4] == 'X' && drawTable[5] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[6] == 'X' && drawTable[7] == 'X' && drawTable[8] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[0] == 'X' && drawTable[4] == 'X' && drawTable[8] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[2] == 'X' && drawTable[4] == 'X' && drawTable[6] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[0] == 'X' && drawTable[3] == 'X' && drawTable[6] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}

else if(drawTable[1] == 'X' && drawTable[4] == 'X' && drawTable[7] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[2] == 'X' && drawTable[5] == 'X' && drawTable[8] == 'X'){
    cout << PLAYER1.name << " won" << endl;
    exit(1);
}
else if(drawTable[0] == 'O' && drawTable[1] == 'O' && drawTable[2] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}

else if(drawTable[3] == 'O' && drawTable[4] == 'O' && drawTable[5] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}

else if(drawTable[6] == 'O' && drawTable[7] == 'O' && drawTable[8] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}

else if(drawTable[0] == 'O' && drawTable[4] == 'O' && drawTable[8] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}
else if(drawTable[2] == 'O' && drawTable[4] == 'O' && drawTable[6] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}
else if(drawTable[0] == 'O' && drawTable[3] == 'O' && drawTable[6] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}
else if(drawTable[1] == 'O' && drawTable[4] == 'O' && drawTable[7] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
}
else if(drawTable[2] == 'O' && drawTable[5] == 'O' && drawTable[8] == 'O'){
    cout << PLAYER2.name << " won" << endl;
    exit(1);
    //    }
    //        else
    //{
    //      cout << "It's a TIE" << endl;
    // }


}

Answer 1

使用while循環和另一個函數獲勝（重構代碼並退出條件）。

main() {
    while(1){
      //do everything here
      //when someone wins call
      someOneWon(name);
   }
}   

功能

void someOneWon(string name){
    char input;
    cout << name << " won" << endl;
    cout << "would you like to play another game ?(Y/N)"<<endl;
    do {
       input = getchar();
       putchar (input);
    }while( input != 'Y' && input != 'N');
    if (input == 'Y')
        return; // reinitilaize the game, set drawTable to starting point
    else
        exit(0);
}

Answer 2

你可以做這樣的事情。 這是在C＃中。 我確定您可以將其轉換為c ++。

string sUserInput = "y";
while(sUserInput.Equals("y")
{

   //Logic of your code.
   Console.WriteLine("Do you play again?")
   sUserInput = Console.Readline();

}