Currently working on a Tic Tac Toe Game ran across a problem with looping the function after a player has won. I tried using, exit(1);
however that just exits out of the entire program, and doesn't allow a loop. What I want is to exit out of the game and prompt the user with ay/n question to loop the game or not. Here is what the function looks like.
void checkwin(char drawTable[]){
if(drawTable[0] == 'X' && drawTable[1] == 'X' && drawTable[2] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[3] == 'X' && drawTable[4] == 'X' && drawTable[5] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[6] == 'X' && drawTable[7] == 'X' && drawTable[8] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[0] == 'X' && drawTable[4] == 'X' && drawTable[8] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[2] == 'X' && drawTable[4] == 'X' && drawTable[6] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[0] == 'X' && drawTable[3] == 'X' && drawTable[6] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[1] == 'X' && drawTable[4] == 'X' && drawTable[7] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[2] == 'X' && drawTable[5] == 'X' && drawTable[8] == 'X'){
cout << PLAYER1.name << " won" << endl;
exit(1);
}
else if(drawTable[0] == 'O' && drawTable[1] == 'O' && drawTable[2] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[3] == 'O' && drawTable[4] == 'O' && drawTable[5] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[6] == 'O' && drawTable[7] == 'O' && drawTable[8] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[0] == 'O' && drawTable[4] == 'O' && drawTable[8] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[2] == 'O' && drawTable[4] == 'O' && drawTable[6] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[0] == 'O' && drawTable[3] == 'O' && drawTable[6] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[1] == 'O' && drawTable[4] == 'O' && drawTable[7] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
}
else if(drawTable[2] == 'O' && drawTable[5] == 'O' && drawTable[8] == 'O'){
cout << PLAYER2.name << " won" << endl;
exit(1);
// }
// else
//{
// cout << "It's a TIE" << endl;
// }
}
use a while loop and another function for win (to refactor the code and exit condition).
main() {
while(1){
//do everything here
//when someone wins call
someOneWon(name);
}
}
function
void someOneWon(string name){
char input;
cout << name << " won" << endl;
cout << "would you like to play another game ?(Y/N)"<<endl;
do {
input = getchar();
putchar (input);
}while( input != 'Y' && input != 'N');
if (input == 'Y')
return; // reinitilaize the game, set drawTable to starting point
else
exit(0);
}
You can do something like this. This is in C#. I'm sure you can convert it in c++.
string sUserInput = "y";
while(sUserInput.Equals("y")
{
//Logic of your code.
Console.WriteLine("Do you play again?")
sUserInput = Console.Readline();
}
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