[英]Multiple column values in where clause
我需要顯示每周的單用戶時間表,如時間表,
場景:一個教師被分配到一個星期的多個批次(例如:BBA,數學和上午的第1小時和第2小時)和(MBA,數學,前三個小時和第4小時)在同一個日期說(30-06-2015)我的gridview行將存儲為1和2行作為存儲為2,依此類推.........
我的表定義:
CREATE TABLE [dbo].[test] (
[datedif] NVARCHAR (50) NOT NULL,
[hour] INT NULL,
[subject] NVARCHAR (MAX) NULL,
[faculty] NVARCHAR (MAX) NULL,
[attendence] BIT NULL,
[dayweek] NVARCHAR (50) NULL,
[weekmonth] NVARCHAR (MAX) NULL,
[batch] NVARCHAR (MAX) NULL,
[section] NVARCHAR (MAX) NULL,
[session] NVARCHAR (MAX) NULL
);
表看起來像:
Datefdiff | hour | subject | faulty| batch
----------+-------+----------+---------+-------+----------+--------+-------+----------+---------+-------
30-06-2015| 1| Maths | Kevin | BBA
30-06-2015| 2| Science | Amal | MBA
30-06-2015|3 | chemistry|Jaya |BBA
30-06-2015|4 | chemistry|Jaya |BBA
30-06-2015|5 | chemistry|Jaya |BBA
31-06-2015 |1| science | Amal |BBA
31-06-2015 |2| Maths | kevin |BBA
31-06-2015 |3| Science | Amal |BBA
31-06-2015 |4 | chemistry|Jaya |BBA
31-06-2015 |5| science | Amal |BBA
只為教師提供預期產出:Amal
Datefdiff |hour|subject| batch |hour|subject | batch |faculty|hour | subject | batch | hour | subject | batch| hour | subject | batch |
----------+-------+----------+-------+-------+----------+-------+-------+----------+
30-06-2015| 1 | Maths| BBA| 2| Science | MBA | 3| Science | BBA| 4| chemistry| BBA | 5 |Physics |MBA
31-06-2015| 1 | Maths| BBA| 2| Science | MBA | 3| Science | BBA| 4| chemistry| BBA | 5 |Physics |MBA
這可能是您的表設計的起點:
declare @tbFaculty table (
FacultyID int --identity(1,1) primary key
, Name varchar(50)
)
insert into @tbFaculty ( FacultyID, Name )
values ( 1, 'Kevin' )
, ( 2, 'Amal' )
declare @tbBatch table(
BatchID int --identity(1,1) primary key
, Name char(3)
)
insert into @tbBatch ( BatchID, Name )
values ( 1, 'BBA' )
, ( 2, 'MBA' )
declare @tbClass table (
[Hour] tinyint
, [Subject] nvarchar (128)
, [FacultyID] int
, [Attendence] bit
, [BatchID] char(3)
, [ClassDate] date
)
insert into @tbClass ( [Hour], [Subject], FacultyID, Attendence, BatchID, ClassDate )
values ( 1, 'Maths', 1, 1, 1, '2015-06-30' )
, ( 2, 'Maths', 1, 1, 1, '2015-06-30' )
, ( 3, 'Science', 2, 1, 1, '2015-06-30' )
, ( 1, 'Science', 2, 1, 2, '2015-06-30' )
, ( 2, 'Science', 2, 1, 2, '2015-06-30' )
, ( 3, 'Maths', 1, 1, 2, '2015-06-30' )
select
cl.ClassDate
, cl.[Hour]
, cl.[Subject]
, ba.Name as BatchName
, fa.Name as FacultyName
from
@tbClass cl
inner join @tbBatch ba on ba.BatchID = cl.BatchID
inner join @tbFaculty fa on fa.FacultyID = cl.FacultyID
where
fa.Name = 'Amal'
您也可以規范化主題。
我只想將此作為單獨的答案添加。 試試這個:
--INSERT INTO dbo.test(datedif,[hour],[subject],faculty,batch)
--VALUES
--('30-06-2015',1,'Maths','Kevin','BBA'),
--('30-06-2015',2,'Science','Amal','MBA'),
--('30-06-2015',3,'chemistry','Jaya','BBA'),
--('30-06-2015',4,'chemistry','Jaya','BBA'),
--('30-06-2015',5,'chemistry','Jaya','BBA'),
--('31-06-2015',1,'science','Amal','BBA'),
--('31-06-2015',2,'Maths','kevin','BBA'),
--('31-06-2015',3,'Science','Amal','BBA'),
--('31-06-2015',4,'chemistry','Jaya','BBA'),
--('31-06-2015',5,'science','Amal','BBA');
WITH CTE_Hours
AS
(
SELECT
1 AS hour1,
MAX(CASE WHEN [Hour] = 1 THEN [subject] END) AS subject1,
MAX(CASE WHEN [Hour] = 1 THEN [batch] END) AS batch1 ,
2 AS hour2,
MAX(CASE WHEN [Hour] = 2 THEN [subject] END) AS subject2,
MAX(CASE WHEN [Hour] = 2 THEN [batch] END) AS batch2
--etc...
FROM dbo.test
WHERE faculty = 'Amal'
)
SELECT *
FROM (
SELECT DISTINCT datedif
FROM dbo.test
) A
CROSS JOIN CTE_Hours
以下是如何規范化您的數據,這將使查詢更加簡單。
使用表定義,我插入了您的數據
INSERT INTO test(Datedif,hour1,subject1,faculty1,hour2,subject2,faculty2,hour3,subject3,faculty3,batch)
VALUES ('30-06-2015',1,'Maths','Kevin',1,'Maths','Kevin',1,'Science','Amal','BBA'),
('30-06-2015',1,'Science','Amal',1,'Science','Amal',1,'Maths','Kevin','MBA');
然后我使用較窄的數據類型為您的數據創建了一個新的規范化結構。 它有助於保持數據清潔以及不浪費存儲空間,這意味着查詢速度更快,因為它們不必處理如此多的數據。
CREATE TABLE new_test
(
dt DATE NULL,
hr TINYINT NULL, --holds values between 0 to 255
subj VARCHAR(100) NULL, --plenty big enough. No need for NVARCHAR unless you are using Unicode characters
faculty VARCHAR(100) NULL,
attendance BIT NULL,
dayweek TINYINT NULL,
weekmonth TINYINT NULL,
section VARCHAR(100) NULL, --not sure what this is
sess VARCHAR(100) NULL, --not sure what this is
batch CHAR(3) NULL --looks like there are three character codes
);
這是我規范化數據的地方。 我不確定你是否有出勤2,3,4等...如果你在實際的表中,那么你應該修復我的代碼。
注意:我計算了從日期開始的每周和每周。 我做了最好的猜測,如果它們不正確,那么隨意調整它們!
WITH norm_data
AS
(
SELECT datedif,hour1,subject1,faculty1,attendence1,dayweek,weekmonth,section,[session],batch FROM test
UNION ALL
SELECT datedif,hour2,subject2,faculty2,attendence1,dayweek,weekmonth,section,[session],batch FROM test
UNION ALL
SELECT datedif,hour3,subject3,faculty3,attendence1,dayweek,weekmonth,section,[session],batch FROM test
UNION ALL
SELECT datedif,hour4,subject4,faculty4,attendence1,dayweek,weekmonth,section,[session],batch FROM test
UNION ALL
SELECT datedif,hour5,subject5,faculty5,attendence1,dayweek,weekmonth,section,[session],batch FROM test
)
INSERT INTO new_test
SELECT PARSE(datedif AS DATE USING 'de-DE') AS [datedif],
hour1,
subject1,
faculty1,
attendence1,
DATEPART(WEEKDAY,PARSE(datedif AS DATE USING 'de-DE')) AS dayweek,
datepart(day, datediff(day, 0, PARSE(datedif AS DATE USING 'de-DE'))/7 * 7)/7 + 1 AS weekmonth,
section,
[session],
batch
FROM norm_data
現在讓我們來看看你的新表
SELECT *
FROM new_test
如果它是正確的,那么這里是如何重命名表
EXEC SP_rename @objname = 'test', --if you don't want to drop the old table
@newname = 'test_old'
EXEC SP_rename @objname = 'new_test', --now give the new table the actual name
@newname = 'test'
SELECT *
FROM test
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