如何在 Unity 中獲取設備的網關？

Question

我正在嘗試在 Android 智能手機上接收 Unity 和 C# 中設備的標准網關，但我無法修復它。

這就是為什么我問是否有可能使用 Unity 和 C# 在 Android 智能手機上找到網關。

我已經嘗試過這個，它在 Unity 編輯器中確實有效：

    NetworkInterface[] adapters = NetworkInterface.GetAllNetworkInterfaces();
    foreach (NetworkInterface adapter in adapters)
    {
        IPInterfaceProperties adapterProperties = adapter.GetIPProperties();
        GatewayIPAddressInformationCollection addresses = adapterProperties.GatewayAddresses;
        if (addresses.Count > 0)
        {
            foreach (GatewayIPAddressInformation address in addresses)
            {
                if (address.Address.ToString() != "0.0.0.0")
                {
                    Debug.Log("Gateway: " + address.Address.ToString());
                }
            }
        }
    }

Answer 1

在電腦上工作：

IPAddress GatewayAddress = NetworkInterface
                .GetAllNetworkInterfaces()
                .Where(n => n.OperationalStatus == OperationalStatus.Up)
                .Where(n => n.NetworkInterfaceType != NetworkInterfaceType.Loopback)
                .Where(n => n.NetworkInterfaceType != NetworkInterfaceType.Loopback)
                .SelectMany(n => n.GetIPProperties()?.GatewayAddresses)
                .Select(g => g?.Address)
                .Where(a => a != null)
                .Where(a => a.AddressFamily == AddressFamily.InterNetwork)
                .FirstOrDefault();

Answer 2

在Assets/Plugins/Android目錄中創建一個Network.java文件。

資產/插件/Android/Network.java

package com.mynet;
 
import java.net.InetAddress;
import java.net.NetworkInterface;
import java.net.SocketException;
import java.util.Enumeration;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
 
 
public class Network{
    //Match the IP of class C address
    public static final String regexCIp = "^192\\.168\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)$";
    //Match a class A address
    public static final String regexAIp = "^10\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)$";
    //Match B address
    public static final String regexBIp = "^172\\.(1[6-9]|2\\d|3[0-1])\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)\\.(\\d{1}|[1-9]\\d|1\\d{2}|2[0-4]\\d|25\\d)$";
 
 
    public  String getHostIp() {
        String hostIp;
        Pattern ip = Pattern.compile("(" + regexAIp + ")|" + "(" + regexBIp + ")|" + "(" + regexCIp + ")");
        Enumeration<NetworkInterface> networkInterfaces = null;
        try {
            networkInterfaces = NetworkInterface.getNetworkInterfaces();
        } catch (SocketException e) {
            e.printStackTrace();
        }
        InetAddress address;
        while (networkInterfaces.hasMoreElements()) {
            NetworkInterface networkInterface = networkInterfaces.nextElement();
            Enumeration<InetAddress> inetAddresses = networkInterface.getInetAddresses();
            while (inetAddresses.hasMoreElements()) {
                address = inetAddresses.nextElement();
                String hostAddress = address.getHostAddress();
                Matcher matcher = ip.matcher(hostAddress);
                if (matcher.matches()) {
                    hostIp = hostAddress;
                    return hostIp;
                }
 
            }
        }
        return null;
    }
}

在C#代碼中使用此腳本，如下所示：

using UnityEngine;
using UnityEngine.UI;

public class MyIPScript: MonoBehaviour
{

    public Text ipText;

    public void Start()
    {
        string ip = GetIP();
        ipText.text = ip;
    }

    private string GetIP() {
        AndroidJavaObject jo = new AndroidJavaObject("com.mynet.Network");
        AndroidJavaClass act = new AndroidJavaClass("com.unity3d.player.UnityPlayer");
        return jo.Call<string>("getHostIp");
    }
}

注意：這僅適用於Android設備。 如果在PC上測試，您將看不到任何 IP 地址。 因此，通過從Build Settings選擇Android並生成apk文件來構建您的 unity 項目，然后將其安裝在您的Android Phone或VR Headset 。 我在Oculus Quest上對其進行了測試，效果很好。