[英]Can't filter nodes on cypher query Neo4j
我有一些數據,如下所示:
(:Artist {id: 1, name: "Depeche Mode"})<-[:PLAYED_BY]-(:Song {id: 1, title: "Enjoy The Silence"})-[:PLAYED_BY]->(:Artist {id: 2, name: "Lacuna Coil"})
例如,我將需要查詢id
1和2的所有PLAYED_BY
Artist Song
。
我在想類似的東西:
MATCH (s:Song)-[:PLAYED_BY]->(a:Artist)
WHERE a.id IN [1, 2]
RETURN s
但這不是我想要的那樣工作:因為它就像一個OR
,我想像AND
使用它。
有什么建議么?
編輯1: Artist
的數量應該是任意的。
EDIT2:我還需要使用全文索引運行此查詢,如下所示:
START song=node:node_auto_index("title:*enjo*")
MATCH ...
RETURN ...
該歌曲也由其他藝術家播放,例如,由Artist [1, 2, 3]
播放的Song 1
。 當我查詢[1,2]
,無論如何應該返回它。
這應該適用於您的示例:
MATCH (a1:Artist)<-[:PLAYED_BY]-(s:Song)-[:PLAYED_BY]->(a2:Artist)
WHERE a1.id = 1 AND a2.id = 2
RETURN s
因此,您想查找歌手1和歌手2播放的歌曲嗎?
該查詢如何:
MATCH (a1:Artist)<-[:PLAYED_BY]-(s:Song)-[:PLAYED_BY]->(a2:Artist)
WHERE a1.id = 1 AND a2.id = 2
RETURN s
編輯
對於任意數量的藝術家:
WITH [1,2] AS ids
MATCH (a:Artist)<-[:PLAYED_BY]-(s:Song)
WITH collect(a.id) AS artistIds, ids,s
WHERE all(x IN artistIds WHERE x IN ids) AND all(x IN ids WHERE x IN artistIds)
RETURN s
收集播放過歌曲的所有藝術家的ID,然后使用Cypher集合謂詞all
僅過濾所需的藝術家ID。
數組[1,2]
可以像這樣被參數化: WITH {id_array} AS ids ...
編輯
使用舊式索引進行模糊文本搜索應適用於這種方法。 只需將MATCH中未綁定(s:Song)
模式的部分替換為由舊索引填充的綁定song
變量:
START song=node:node_auto_index("title:*enjo*")
WITH [1,2] AS ids, song
MATCH (a:Artist)<-[:PLAYED_BY]-(song)
WITH collect(a.id) AS artistIds, ids, song
WHERE all(x IN artistIds WHERE x IN ids) AND all(x IN ids WHERE x IN artistIds)
RETURN s
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