[英]Can't filter nodes on cypher query Neo4j
我有一些数据,如下所示:
(:Artist {id: 1, name: "Depeche Mode"})<-[:PLAYED_BY]-(:Song {id: 1, title: "Enjoy The Silence"})-[:PLAYED_BY]->(:Artist {id: 2, name: "Lacuna Coil"})
例如,我将需要查询id
1和2的所有PLAYED_BY
Artist Song
。
我在想类似的东西:
MATCH (s:Song)-[:PLAYED_BY]->(a:Artist)
WHERE a.id IN [1, 2]
RETURN s
但这不是我想要的那样工作:因为它就像一个OR
,我想像AND
使用它。
有什么建议么?
编辑1: Artist
的数量应该是任意的。
EDIT2:我还需要使用全文索引运行此查询,如下所示:
START song=node:node_auto_index("title:*enjo*")
MATCH ...
RETURN ...
该歌曲也由其他艺术家播放,例如,由Artist [1, 2, 3]
播放的Song 1
。 当我查询[1,2]
,无论如何应该返回它。
这应该适用于您的示例:
MATCH (a1:Artist)<-[:PLAYED_BY]-(s:Song)-[:PLAYED_BY]->(a2:Artist)
WHERE a1.id = 1 AND a2.id = 2
RETURN s
因此,您想查找歌手1和歌手2播放的歌曲吗?
该查询如何:
MATCH (a1:Artist)<-[:PLAYED_BY]-(s:Song)-[:PLAYED_BY]->(a2:Artist)
WHERE a1.id = 1 AND a2.id = 2
RETURN s
编辑
对于任意数量的艺术家:
WITH [1,2] AS ids
MATCH (a:Artist)<-[:PLAYED_BY]-(s:Song)
WITH collect(a.id) AS artistIds, ids,s
WHERE all(x IN artistIds WHERE x IN ids) AND all(x IN ids WHERE x IN artistIds)
RETURN s
收集播放过歌曲的所有艺术家的ID,然后使用Cypher集合谓词all
仅过滤所需的艺术家ID。
数组[1,2]
可以像这样被参数化: WITH {id_array} AS ids ...
编辑
使用旧式索引进行模糊文本搜索应适用于这种方法。 只需将MATCH中未绑定(s:Song)
模式的部分替换为由旧索引填充的绑定song
变量:
START song=node:node_auto_index("title:*enjo*")
WITH [1,2] AS ids, song
MATCH (a:Artist)<-[:PLAYED_BY]-(song)
WITH collect(a.id) AS artistIds, ids, song
WHERE all(x IN artistIds WHERE x IN ids) AND all(x IN ids WHERE x IN artistIds)
RETURN s
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