[英]Highlighting Unbalanced Parentheses in RichTextBox C# Windows Forms
我目前有一個Windows窗體設置,該窗體在RichTextBox內接受一個數學表達式,並在表達式中搜索任何不平衡的括號。 我的表單包含RichTextBox和一個顯示“檢查Parens”的按鈕。 我也在嘗試使用堆棧檢查不平衡的括號。 我想要以某種方式指出哪些括號是不平衡的。 我想通過突出顯示或加粗RichTextBox內的括號來做到這一點。 有沒有辦法用我現在設置的代碼來做到這一點? 這是我的下面代碼,任何建設性的反饋將不勝感激!
public partial class checkParentheses : Form
{
const char leftParens = '(';
const char rightParens = ')';
public checkParentheses()
{
InitializeComponent();
}
public void checkParensButton_Click(object sender, EventArgs e)
{
int value;
checkBalancedParens(mathEquation.Text, out value);
}
bool checkBalancedParens(string expression, out int error)
{
var parens = new Stack<int>(expression.Length);//Create stack
error = -1; //Error at -1
for (int i = 0; i < expression.Length; i++)//Check for unbalanced Parentheses
{
char p = expression[i];
if (p == leftParens)//if p finds left parens
{
parens.Push(i);//push to top of stack
}
else if (p == rightParens)//if p finds right parens
{
if (parens.Count == 0)//if stack has zero items
{
error = i + 1;
return false;
}
parens.Pop();//Returns to top of stack
}
}
if (parens.Count > 0)//if stack has more than 0 items
{
error = parens.Peek() + 1; //Peek at top of stack
MessageBox.Show("Unbalanced");
return false;
}
MessageBox.Show("Balanced");//Otherwise, expression is balanced
return true;
}
}
編輯:給定下面的解決方案,這是次等的。 如果要加粗文本,則仍包含示例。 您可以將HighlightOffenders方法替換為
private void HighlightOffenders(IEnumerable<int> listOfIndexes)
{
foreach (var index in listOfIndexes.Reverse())
{
mathEquation.Select(index,1);
mathEquation.SelectionFont = new Font(mathEquation.Font, FontStyle.Bold);
}
}
因此,您應該同時跟蹤左側paren索引和右側paren索引。 然后只需將匹配對彈出各自的堆棧即可。
至於顯示文本,我不知道這是否是最好的方法,但是這是可行的方法。 它需要重建字符串,但會將正確的結果放入RichTextBox中。 您將需要忽略我的表單稱為“ Form1”的事實,而應將其替換為“ checkParentheses”。 可能有一種方法可以在實際字符上突出顯示突出顯示的內容,但是我對此並不熟悉。
public partial class Form1 : Form
{
const char leftParenChar = '(';
const char rightParenChar = ')';
public Form1()
{
InitializeComponent();
}
public void checkParensButton_Click(object sender, EventArgs e)
{
checkBalancedParens(mathEquation.Text);
}
bool checkBalancedParens(string expression)
{
var leftParensIndexes = new Stack<int>(expression.Length);
var rightParensIndexes = new Stack<int>(expression.Length);
var isError = false;
for (int i = 0; i < expression.Length; i++)//Check for unbalanced Parentheses
{
char p = expression[i];
if (p == leftParenChar)//if p finds left parens
{
leftParensIndexes.Push(i);//push to top of stack
}
else if (p == rightParenChar)//if p finds right parens
{
rightParensIndexes.Push(i);
//keep a record if there is an error, but don't stop yet.
if (leftParensIndexes.Count == 0)
{
isError = true;
}
else
{
//eliminate the matching pair if it exists
rightParensIndexes.Pop();
leftParensIndexes.Pop();
}
}
}
if (leftParensIndexes.Count > 0)//if stack has more than 0 items
{
isError = true;
}
HighlightOffenders(rightParensIndexes.Concat(leftParensIndexes));
return !isError;
}
private void HighlightOffenders(IEnumerable<int> listOfIndexes)
{
var text = mathEquation.Text;
mathEquation.Clear();
int lastIndex = 0; //store the last index you finished at (for string math)
int count = 0; //the number of items that we've added (also for string math)
foreach (var index in listOfIndexes.Reverse())
{
mathEquation.AppendText(text.Substring(lastIndex, index - lastIndex - count));
mathEquation.SelectionFont = new Font(mathEquation.Font, FontStyle.Bold);
mathEquation.AppendText(text.Substring(index,1));
mathEquation.SelectionFont = new Font(mathEquation.Font, FontStyle.Regular);
lastIndex = index;
count++;
}
mathEquation.AppendText(text.Substring(lastIndex + count-1, text.Length - lastIndex - count + 1));
}
}
此處描述的在RichEdit中突出顯示文本。 完整的解決方案:
private void checkParensButton_Click(object sender, EventArgs e)
{
// clean up previous selection
mathEquation.SelectAll();
mathEquation.SelectionBackColor = Color.White;
var indexes = EnumerateUnbalancedParentheses(mathEquation.Text);
foreach (var index in indexes)
{
mathEquation.Select(index, 1);
mathEquation.SelectionBackColor = Color.Aqua;
}
}
private static IEnumerable<int> EnumerateUnbalancedParentheses(string expression)
{
var openingParentheses = new Stack<int>();
var closingParentheses = new Stack<int>();
for (var i = 0; i < expression.Length; ++i)
{
var symbol = expression[i];
if (symbol == '(')
{
openingParentheses.Push(i);
}
else if (symbol == ')')
{
if (openingParentheses.Count > 0)
openingParentheses.Pop();
else
closingParentheses.Push(i);
}
}
return openingParentheses.Concat(closingParentheses);
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.