[英]XML Serializing a Class results Empty XML
我正在嘗試以可讀格式(XML)保存類。 問題是,生成的文件僅輸出為:
<?xml version="1.0" encoding="Windows-1252"?>
<ExtremeLearningMachine xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" /><?xml version="1.0" encoding="Windows-1252"?>
<ExtremeLearningMachine xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" /><?xml version="1.0" encoding="Windows-1252"?>
<ExtremeLearningMachine xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" /><?xml version="1.0" encoding="Windows-1252"?>
<ExtremeLearningMachine xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" />
這是我的課:
public class ExtremeLearningMachine {
public ExtremeLearningMachine()
{
}
int input, hidden; //only have 1 output neuron
double[,] W1, W2;
public ExtremeLearningMachine(int inputNeuron, int hiddenNeuron) { input = inputNeuron; hidden = hiddenNeuron; }
public void train(int dataCount, double[,] trainingSet) {
//set matrix
double[,] trainInput = new double[input, dataCount], desireOutput = new double[1, dataCount];
for (int i = 0; i < dataCount; i++) {
for (int j = 0; j < input; j++) trainInput[j, i] = trainingSet[i, j];
desireOutput[0, i] = trainingSet[i, input];
}
//W1
W1 = new double[hidden, input];
for (int i = 0; i < hidden; i++) { for (int j = 0; j < input; j++)W1[i, j] = Random.value; }
//hidden
//double[,] H = new double[hidden, dataCount];
double[,] H = Matrix.Multiply(W1, trainInput);
//activation function(binary sigmoid)
for (int i = 0; i < hidden; i++) {
for (int j = 0; j < dataCount; j++) H[i, j] = 1f / (1f + Mathf.Exp((float)-H[i, j]));
}
//W2
W2 = Matrix.Multiply(desireOutput, H.PseudoInverse());
}
public double test(double[,] set) {//only [~,1] allowed
double[,] H = Matrix.Multiply(W1, set.Transpose());
//activation function(binary sigmoid)
for (int i = 0; i < hidden; i++) H[i, 0] = 1f / (1f + Mathf.Exp((float)-H[i, 0]));
H = Matrix.Multiply(W2, H);
return H[0, 0];
}
}
這是我的保存代碼:
void save()
{
System.Xml.Serialization.XmlSerializer writer =
new System.Xml.Serialization.XmlSerializer(typeof(ExtremeLearningMachine));
string path = Directory.GetCurrentDirectory() + "\\ElmTrain.xml";
System.IO.FileStream file = System.IO.File.Create(path);
for(int i=0;i<elm.Length;i++)
writer.Serialize(file, elm[i]);
file.Close();
}
還有我的加載代碼,以防萬一(我還無法保存,所以我尚未對其進行測試):
void load()
{
System.Xml.Serialization.XmlSerializer reader =
new System.Xml.Serialization.XmlSerializer(typeof(ExtremeLearningMachine));
System.IO.StreamReader file = new System.IO.StreamReader("//ElmTrain.xml");
elm = (ExtremeLearningMachine[])reader.Deserialize(file);
file.Close();
}
如果建議的話,我也願意采用其他可讀格式保存此類的其他想法
非常感謝你
首先, ExtremeLearningMachine
沒有任何公共成員要序列化,所以是的:期望它為空; XmlSerializer
僅序列化公共字段和屬性 。 例如,嘗試添加公共屬性來補充您的私有字段。
其次:不要將多個片段序列化到同一文檔。 而是創建一個容器 ,並對其進行序列化。 坦白說,您可以只使用ExtremeLearningMachine[]
作為容器,因為您已經擁有了:
var writer = new XmlSerializer(typeof(ExtremeLearningMachine[]));
string path = Path.Combine(Directory.GetCurrentDirectory(), "ElmTrain.xml");
using(var file = File.Create(path)) {
writer.Serialize(file, elm);
}
和:
var reader = new XmlSerializer(typeof(ExtremeLearningMachine[]));
using(var file = File.OpenRead(path)) {
elm = (ExtremeLearningMachine[])reader.Deserialize(file);
}
轉換時嘗試以下代碼:
XmlSerializer serializer = new XmlSerializer(typeof(ExtremeLearningMachine ));
MemoryStream memStream = new MemoryStream();
serializer.Serialize(memStream, elm);
FileStream file = new FileStream(folderName + "\\ElmTrain.xml", FileMode.Create, FileAccess.ReadWrite);//Provide correct path as foldername
memStream.WriteTo(file);
file.Close();
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