來自具有頻率 python 的數據幀的 WordCloud

Question

我有一個如下的數據框

Int64Index: 14830 entries, 25791 to 10668
Data columns (total 2 columns):
word    14830 non-null object
coef    14830 non-null float64
dtypes: float64(1), object(1)

我試着用 coef 作為頻率來制作詞雲，而不是算作充足

text = df['word']
WordCloud.generate_from_text(text)
TypeError: generate_from_text() missing 1 required positional argument: 'text'

或

text = np.array(df['word'])
WordCloud.generate_from_text(text)
TypeError: generate_from_text() missing 1 required positional argument: 'text'

我該如何改進此代碼並制作這樣的詞雲

from wordcloud import WordCloud
wordcloud = WordCloud( ranks_only= frequency).generate(text)
plt.imshow(wordcloud)
plt.axis('off')
plt.show()

謝謝

Answer 1

對我來說，它創建了一本字典，如下所示：

d = {}
for a, x in bag.values:
    d[a] = x

import matplotlib.pyplot as plt
from wordcloud import WordCloud

wordcloud = WordCloud()
wordcloud.generate_from_frequencies(frequencies=d)
plt.figure()
plt.imshow(wordcloud, interpolation="bilinear")
plt.axis("off")
plt.show()

其中bag是一個包含單詞和計數列的 Pandas DataFrame

Answer 2

首先我們得到元組列表

tuples = [tuple(x) for x in df.values]

那么

wordcloud = WordCloud().generate_from_frequencies(dict(tuples))

僅此而已