在 Python 中將時間從 AM/PM 格式轉換為軍用時間

Question

在不使用任何庫的情況下，我試圖解決 Hackerrank 問題“ 時間轉換”，其問題陳述復制如下。

我想出了以下內容：

time = raw_input().strip()

meridian = time[-2:]        # "AM" or "PM"
time_without_meridian = time[:-2]
hour = int(time[:2])

if meridian == "AM":
    hour = (hour+1) % 12 - 1
    print ("%02d" % hour) + time_without_meridian[2:]
elif meridian == "PM":
    hour += 12
    print str(hour) + time_without_meridian[2:]

但是，這在一個測試用例上失敗了：

但是，由於測試用例對用戶是隱藏的，所以我很難找出問題發生在哪里。 “12:00:00AM”正確轉換為“00:00:00”，“01:00:00AM”正確轉換為“01:00:00”（填充零）。 這個實現可能有什么問題？

Answer 1

它甚至比你擁有它的方式更簡單。

hour = int(time[:2])
meridian = time[8:]
# Special-case '12AM' -> 0, '12PM' -> 12 (not 24)
if (hour == 12):
    hour = 0
if (meridian == 'PM'):
    hour += 12
print("%02d" % hour + time[2:8])

Answer 2

您已經解決了問題，但這里有另一個可能的答案：

from datetime import datetime


def solution(time):
    return datetime.strptime(time, '%I:%M:%S%p').strftime('%H:%M:%S')


if __name__ == '__main__':
    tests = [
        "12:00:00PM",
        "12:00:00AM",
        "07:05:45PM"
    ]
    for t in tests:
        print solution(t)

雖然它會使用 python 庫:-)

Answer 3

我想通了：它正在將“12:00:00PM”轉換為“24:00:00”而不是“12:00:00”。 我修改了代碼如下：

time = raw_input().strip()

meridian = time[-2:]        # "AM" or "PM"
time_without_meridian = time[:-2]
hour = int(time[:2])

if meridian == "AM":
    hour = (hour+1) % 12 - 1
    print ("%02d" % hour) + time_without_meridian[2:]
elif meridian == "PM":
    hour = hour % 12 + 12
    print str(hour) + time_without_meridian[2:]

導致它通過所有測試用例（見下文）。

Answer 4

from datetime import datetime

#Note the leading zero in 05 below, which is required for the formats used below

regular_time = input("Enter a regular time in 05:48 PM format: ")

#%I is for regular time. %H is for 24 hr time, aka "military time"
#%p is for AM/PM

military_time = datetime.strptime(regtime, '%I:%M %p').strftime('%H:%M')

print(f"regular time is: {regular_time"}
print(f"militarytime is {military_time}")

事實證明，以下鏈接非常有用： https : //strftime.org/

Answer 5

dt_m = datetime.datetime.fromtimestamp(m_time)
hour_m = (dt_m.hour%12)+1  #dt_m.hour+1
offset_dt = datetime.datetime(dt_m.year, dt_m.month, dt_m.day, hour_m , dt_m.minute, dt_m.second, dt_m.microsecond)