簡體   English   中英

如何避免JSON百分比編碼和\\ u轉義?

[英]How can I avoid JSON percent-encoding and \u-escaping?

當我解析文件時

<html>
    <head><meta charset="UTF-8"></head>
    <body><a href="Düsseldorf.html">Düsseldorf</a></body>
</html>

使用

item = SimpleItem()
item['name'] = response.xpath('//a/text()')[0].extract()
item["url"] = response.xpath('//a/@href')[0].extract()
return item

我最終要么\\u\u003c/code>轉義

[{
    "name": "D\u00fcsseldorf",
    "url": "D\u00fcsseldorf.html"
}]

或帶有百分比編碼的字符串

D%C3%BCsseldorf

這里描述的項目導出器

# -*- coding: utf-8 -*-
import json
from scrapy.contrib.exporter import BaseItemExporter

class UnicodeJsonLinesItemExporter(BaseItemExporter):

    def __init__(self, file, **kwargs):
        self._configure(kwargs)
        self.file = file
        self.encoder = json.JSONEncoder(ensure_ascii=False, **kwargs)

    def export_item(self, item):
        itemdict = dict(self._get_serialized_fields(item))
        self.file.write(self.encoder.encode(itemdict) + '\n')

以及適當的Feed導出程序設置

FEED_EXPORTERS = {
    'json': 'myproj.exporter.UnicodeJsonLinesItemExporter',
}

沒有幫助。

如何獲得utf-8編碼的JSON輸出?

我要重申/擴大一個未解決的問題

更新

與Scrapy正交,請注意,未設置

export PYTHONIOENCODING="utf_8"

跑步

> echo { \"name\": \"Düsseldorf\", \"url\": \"Düsseldorf.html\" } > dorf.json
> python -c'import fileinput, json;print json.dumps(json.loads("".join(fileinput.input())),sort_keys=True, indent=4, ensure_ascii=False)' dorf.json > dorf_pp.json

將失敗

Traceback (most recent call last):
  File "<string>", line 1, in <module>
UnicodeEncodeError: 'ascii' codec can't encode character u'\xfc' in position 16: ordinal not in range(128)

更新

如前所述,我的問題無法回答。 UnicodeJsonLinesItemExporter可以工作,但管道的另一部分是罪魁禍首:作為漂亮地打印JSON輸出的后期處理,我正在使用python -m json.tool in.json > out.json

>>> a = [{
    "name": "D\u00fcsseldorf",
    "url": "D\u00fcsseldorf.html"
}]
>>> a
[{'url': 'Düsseldorf.html', 'name': 'Düsseldorf'}]
>>> json.dumps(a, ensure_ascii=False)
'[{"url": "Düsseldorf.html", "name": "Düsseldorf"}]'

這似乎對我有用

# -*- coding: utf-8 -*-
import scrapy
import urllib

class SimpleItem(scrapy.Item):
    name = scrapy.Field()
    url = scrapy.Field()

class CitiesSpider(scrapy.Spider):
    name = "cities"
    allowed_domains = ["sitercity.info"]
    start_urls = (
        'http://en.sistercity.info/countries/de.html',
    )

    def parse(self, response):
        for a in response.css('a'):
            item = SimpleItem()
            item['name'] = a.css('::text').extract_first()
            item['url'] = urllib.unquote(
                a.css('::attr(href)').extract_first().encode('ascii')
                ).decode('utf8')
            yield item

使用您問題中引用的Feed導出程序,它還可以使用另一個存儲設備

# -*- coding: utf-8 -*-
import json
import io
import os
from scrapy.contrib.exporter import BaseItemExporter
from w3lib.url import file_uri_to_path

class CustomFileFeedStorage(object):

    def __init__(self, uri):
        self.path = file_uri_to_path(uri)

    def open(self, spider):
        dirname = os.path.dirname(self.path)
        if dirname and not os.path.exists(dirname):
            os.makedirs(dirname)
        return io.open(self.path, mode='ab')

    def store(self, file):
        file.close()

class UnicodeJsonLinesItemExporter(BaseItemExporter):

    def __init__(self, file, **kwargs):
        self._configure(kwargs)
        self.file = file
        self.encoder = json.JSONEncoder(ensure_ascii=False, **kwargs)

    def export_item(self, item):
        itemdict = dict(self._get_serialized_fields(item))
        self.file.write(self.encoder.encode(itemdict) + '\n')

(如有必要,刪除評論)

FEED_EXPORTERS = {
    'json': 'myproj.exporter.UnicodeJsonLinesItemExporter'
}
#FEED_STORAGES = {
#   '': 'myproj.exporter.CustomFileFeedStorage'
#}
FEED_FORMAT = 'json'
FEED_URI = "out.json"

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM