How can I avoid JSON percent-encoding and \u-escaping?
Question
When I parse the file
<html>
<head><meta charset="UTF-8"></head>
<body><a href="Düsseldorf.html">Düsseldorf</a></body>
</html>
using
item = SimpleItem()
item['name'] = response.xpath('//a/text()')[0].extract()
item["url"] = response.xpath('//a/@href')[0].extract()
return item
I end up with either \\u\u003c/code> escapes
[{
"name": "D\u00fcsseldorf",
"url": "D\u00fcsseldorf.html"
}]
or with percent-encoded strings
D%C3%BCsseldorf
The item exporter described here
# -*- coding: utf-8 -*-
import json
from scrapy.contrib.exporter import BaseItemExporter
class UnicodeJsonLinesItemExporter(BaseItemExporter):
def __init__(self, file, **kwargs):
self._configure(kwargs)
self.file = file
self.encoder = json.JSONEncoder(ensure_ascii=False, **kwargs)
def export_item(self, item):
itemdict = dict(self._get_serialized_fields(item))
self.file.write(self.encoder.encode(itemdict) + '\n')
along with the appropriate feed exporter setting
FEED_EXPORTERS = {
'json': 'myproj.exporter.UnicodeJsonLinesItemExporter',
}
do not help.
How do I get a utf-8-encoded JSON output?
I'm reiterating/expanding an unanswered question .
Update :
Orthogonal to Scrapy, note that without setting
export PYTHONIOENCODING="utf_8"
running
> echo { \"name\": \"Düsseldorf\", \"url\": \"Düsseldorf.html\" } > dorf.json
> python -c'import fileinput, json;print json.dumps(json.loads("".join(fileinput.input())),sort_keys=True, indent=4, ensure_ascii=False)' dorf.json > dorf_pp.json
will fail with
Traceback (most recent call last):
File "<string>", line 1, in <module>
UnicodeEncodeError: 'ascii' codec can't encode character u'\xfc' in position 16: ordinal not in range(128)
Update
As posted my question was unanswerable. The UnicodeJsonLinesItemExporter works, but another part of the pipeline was the culprit: As a post-process to pretty-print the JSON output, I was was using python -m json.tool in.json > out.json .
2 answers
solution1
2 2016-09-18 04:46:24
>>> a = [{
"name": "D\u00fcsseldorf",
"url": "D\u00fcsseldorf.html"
}]
>>> a
[{'url': 'Düsseldorf.html', 'name': 'Düsseldorf'}]
>>> json.dumps(a, ensure_ascii=False)
'[{"url": "Düsseldorf.html", "name": "Düsseldorf"}]'
solution2
1 ACCPTED 2016-09-19 10:07:10
this seems to work for me
# -*- coding: utf-8 -*-
import scrapy
import urllib
class SimpleItem(scrapy.Item):
name = scrapy.Field()
url = scrapy.Field()
class CitiesSpider(scrapy.Spider):
name = "cities"
allowed_domains = ["sitercity.info"]
start_urls = (
'http://en.sistercity.info/countries/de.html',
)
def parse(self, response):
for a in response.css('a'):
item = SimpleItem()
item['name'] = a.css('::text').extract_first()
item['url'] = urllib.unquote(
a.css('::attr(href)').extract_first().encode('ascii')
).decode('utf8')
yield item
using the feed exporter cited in your question, it worked also using another storage
# -*- coding: utf-8 -*-
import json
import io
import os
from scrapy.contrib.exporter import BaseItemExporter
from w3lib.url import file_uri_to_path
class CustomFileFeedStorage(object):
def __init__(self, uri):
self.path = file_uri_to_path(uri)
def open(self, spider):
dirname = os.path.dirname(self.path)
if dirname and not os.path.exists(dirname):
os.makedirs(dirname)
return io.open(self.path, mode='ab')
def store(self, file):
file.close()
class UnicodeJsonLinesItemExporter(BaseItemExporter):
def __init__(self, file, **kwargs):
self._configure(kwargs)
self.file = file
self.encoder = json.JSONEncoder(ensure_ascii=False, **kwargs)
def export_item(self, item):
itemdict = dict(self._get_serialized_fields(item))
self.file.write(self.encoder.encode(itemdict) + '\n')
(removing the comments if necessary)
FEED_EXPORTERS = {
'json': 'myproj.exporter.UnicodeJsonLinesItemExporter'
}
#FEED_STORAGES = {
# '': 'myproj.exporter.CustomFileFeedStorage'
#}
FEED_FORMAT = 'json'
FEED_URI = "out.json"
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