沒有編寫C ++ char嗎？

Question

我正在從事銀行計划，但遇到了一個奇怪的問題

cin >>任務；

應該啟動一個開關。 但它會不斷跳過輸入並結束程序。

我什至手頭有一個例子，該代碼有效，但是我不確定我做錯了什么。

#include<iostream>
#include<conio.h>
#include<string>
#include <ctype.h>
using namespace     std;

int main()
{

    string name = "";
    int count;

    char task;
    double bal = 0;

    int depo, withd;
    cout << "Welcome to bank of the future! Please sign in" << endl;

    cin >> name;

    cout << "Enter your account number." << endl;
    cin >> count;
    cout << "Welcome back " << name << " What would you like to do?";

    cout << "\n A. Deposit \n B. Withdraw \n C. Show balance \n D. Quit" << endl;


    cin >> task;

    //just to check if it's being skipped over or not.
    cout << "egg " << endl;

    switch (task)
    {
    case 'A':
        cout << "Enter an amount to deposit" << endl;
        cin >> depo;
        cout << "Prevous balance: " << bal << endl;
        bal = bal + depo;
        cout << "New balance: " << bal << endl;
        break;

    case 'B':
        cout << "Enter an amount to withdraw" << endl;
        cin >> withd;
        cout << "Prevous balance: " << bal << endl;
        bal = bal - withd;
        cout << "New balance: " << bal << endl;
        break;
    case 'C':
        cout << "Your current balance is " << bal << "\n For account: " << name << "Acount number: " << count << endl;
        break;
    case 'D':
        cout << "Goodbye forever" << endl;
        break;

    }


    return 0;

}

Answer 1

我認為這可能與char是大寫還是小寫有關。 在開關中，您指定任務為大寫。 當我嘗試使用大寫字母的代碼時，它對我有用，但是當我輸入小寫字母時，它結束了程序。