創建房間沒有重載方法錯誤

Question

當我嘗試使用PhotonNetwork.CreateRoom()函數時出現錯誤。 我正在嘗試傳遞6個參數。

我的Unity版本是4.7.2 ，此功能來自光子雲插件。

CheckPlayerNameAndRoom();
PhotonNetwork.player.name = playerName;
Hashtable setMapName = new Hashtable();
setMapName["MapName"] = allMaps[selectedMap].mapName;
setMapName["RoundDuration"] = roundDuration;
setMapName["GameMode"] = gameMode;
string[] exposedProps = new string[3];
exposedProps[0] = "MapName";
exposedProps[1] = "RoundDuration";
exposedProps[2] = "GameMode";
//Create new Room
PhotonNetwork.CreateRoom(newRoomName, true, true, maxPlayers, setMapName, exposedProps); 

Answer 1

這僅表示您將錯誤的參數傳遞給CreateRoom函數。

根據光子文檔 ， CreateRoom函數有3個重載。

static bool CreateRoom (string roomName)

static bool CreateRoom (string roomName, RoomOptions roomOptions, TypedLobby typedLobby)

static bool CreateRoom (string roomName, RoomOptions roomOptions, TypedLobby typedLobby, string[] expectedUsers)

這些功能均不采用bool或6個參數。 遇到此類問題時，請始終檢查文檔。

下面是有關如何使用每種方法重載的示例。

string newRoomName = "AloneWolf";

if(CreateRoom (newRoomName))
{
    //Success
}

要么

string newRoomName = "AloneWolf";
RoomOptions roomOptions = new RoomOptions();
TypedLobby typedLobby = new TypedLobby ();

if(CreateRoom (newRoomName, roomOptions, typedLobby))
{
    //Success
}

要么

string newRoomName = "AloneWolf";
RoomOptions roomOptions = new RoomOptions();
TypedLobby typedLobby = new TypedLobby ();
string[] expectedUsers = { "AloneWolf","OtherUsers"};

if(CreateRoom (newRoomName, roomOptions, typedLobby, expectedUsers))
{
    //Success
}

Answer 2

謝謝你的回答，我寫這段代碼

 Hashtable roomProps = new Hashtable() { { "MapName", allMaps[selectedMap].mapName }, { "RoundDuration", roundDuration },{ "GameMode", gameMode } }; string[] roomPropsInLobby = { "MapName", "RoundDuration" ,"GameMode" }; RoomOptions roomOptions = new RoomOptions(); roomOptions.customRoomProperties = roomProps; roomOptions.customRoomPropertiesForLobby = roomPropsInLobby; roomOptions.isVisible = true; roomOptions.maxPlayers = (byte)maxPlayers; PhotonNetwork.CreateRoom(newRoomName,roomOptions,TypedLobby.Default); 

它可以使人們加入游戲並看到房間中的最多玩家。 再次感謝您好運。