[英]Divding property by property in LINQ expression
我寫了如下代碼:
Session["priceRange"] = ranges.Select(r => new PriceRangeGraph
{
Price = Math.Round(r, 2),
Sales = lista.Where(x => ranges.FirstOrDefault(y => y >= x.SalePrice) == r).Sum(x => x.SaleNumber),
SuccessfulSellers = lista.GroupBy(x => x.StoreName).Where(x => ranges.FirstOrDefault(y => y >= x.Select(z => z.SalePrice).FirstOrDefault()) == r && x.Select(h => h.SaleNumber).FirstOrDefault() > 0).Count(),
UnSuccessfulSellers = lista.GroupBy(x => x.StoreName).Where(x => ranges.FirstOrDefault(y => y >= x.Select(z => z.SalePrice).FirstOrDefault()) == r && x.Select(h => h.SaleNumber).FirstOrDefault() == 0).Count(),
}).ToList();
其作用如下:
現在,我想為有銷售和無銷售的賣家獲得成功的銷售率。 我這樣做的方式是:
(thoseWhoHadSales/(thoseWhoHadSales+thoseWhoDidnt))*100;
在給定的價格范圍內,我將獲得賣方成功銷售的機會。
現在,我感到困惑的是確實發生/可能發生的異常:
Divide by zero exception... If those who had sales is equal to = 0;
現在,執行我上面顯示的公式最簡單的方法是什么。 我可以立即在select語句中執行此操作嗎?
如果在給定價格范圍內有銷售量的那些人= 0,那么我只需將賣方設置為0 ...
有人可以幫我嗎?
斯蒂芬,你的意思是這樣的:
public double SellThroughRate
{
get { return SellThroughRate; }
set
{
if (SuccessfulSellers != 0)
{
SellThroughRate = Math.Round((SuccessfulSellers / (SuccessfulSellers + UnSuccessfulSellers)) * 100,2);
}
else
{
SellThroughRate = 0;
}
}
}
double.IsNaN()
可以替代檢查等於零的條件,
double tempResult = Math.Round(((double)SuccessfulSellers / ((double)SuccessfulSellers + (double)UnSuccessfulSellers)) * 100,2);
SellThroughRate = double.IsNaN(tempResult) ? 0 : tempResult;
希望有幫助,
將您的屬性設置為只讀,並有條件地檢查SuccessfulSellers + UnSuccessfulSellers
是否為零,以防止出現異常。 我還建議您按原樣存儲結果,並使用[DisplayFormat]
屬性在視圖中顯示格式化的結果
[DisplayFormat(DataFormatString = "{0:P2}")]
public double SellThroughRate
{
get
{
double total = SuccessfulSellers + UnSuccessfulSeller;
return total == 0 ? 0 : SuccessfulSellers / total;
}
};
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