[英]how to combine 2D arrays into a 3D array in python?
我有一個項目,其中有一個 for 循環運行了大約 14 次。 在每次迭代中,都會創建一個具有此形狀 (4,3) 的二維數組。 我想將這些 2D 數組連接成一個 3D 數組(形狀為 4,3,14),以便每個 2D 數組都位於不同的“層”中。 這應該如何在 Python 中實現?
您可以使用numpy.dstack()
將 2D 數組列表轉換為 3D 數組:
https://docs.scipy.org/doc/numpy/reference/generated/numpy.dstack.html
如果您提到的數組大小是靜態的,則可以執行以下操作
output_array = numpy.zeros((14,4,3), dtype=np.float32)
for i in range(14):
mat = numpy.random.rand(4,3)
output_array[i] = mat
您將最終數組初始化為您想要的大小,然后循環並將您的矩陣 (4,3) 分配給相應循環計數器的索引。
形狀和你的最終矩陣是
numpy.shape(output_array)
回報你
(14, 4, 3)
輸出是
array([[[ 0.62507486, 0.3246161 , 0.43934602],
[ 0.14476213, 0.76139957, 0.92813474],
[ 0.26556504, 0.02475475, 0.90740073],
[ 0.08017973, 0.97526789, 0.2213122 ]],
[[ 0.70042586, 0.8122381 , 0.79289031],
[ 0.0369414 , 0.10780825, 0.77501732],
[ 0.10386232, 0.86237574, 0.5829311 ],
[ 0.1888348 , 0.85105735, 0.31599012]],
[[ 0.26350111, 0.8787083 , 0.12869285],
[ 0.25927794, 0.25701383, 0.81212741],
[ 0.06661031, 0.53449911, 0.50212061],
[ 0.40009728, 0.78002244, 0.81524432]],
[[ 0.49921468, 0.82028496, 0.51261139],
[ 0.62790054, 0.64566481, 0.02624587],
[ 0.39364958, 0.99537313, 0.33225098],
[ 0.88214922, 0.20252077, 0.78350848]],
[[ 0.29032609, 0.95975012, 0.06733917],
[ 0.24497923, 0.51818371, 0.93520784],
[ 0.80267638, 0.88271469, 0.30779642],
[ 0.57030594, 0.34175804, 0.52563131]],
[[ 0.61039209, 0.57186425, 0.76554799],
[ 0.55681604, 0.33107477, 0.05680386],
[ 0.15465826, 0.13452645, 0.09498007],
[ 0.29682869, 0.93196124, 0.94435322]],
[[ 0.23904459, 0.94893754, 0.97033942],
[ 0.89159942, 0.85306913, 0.02144577],
[ 0.57696968, 0.82578647, 0.33358794],
[ 0.81979036, 0.73351973, 0.027876 ]],
[[ 0.6568135 , 0.25458351, 0.10369358],
[ 0.06151289, 0.00939822, 0.00798484],
[ 0.92518032, 0.19057493, 0.84838325],
[ 0.78189474, 0.15273546, 0.34607282]],
[[ 0.46961641, 0.19778872, 0.1498462 ],
[ 0.55704814, 0.96889585, 0.08894933],
[ 0.48003736, 0.59383452, 0.42212519],
[ 0.78752649, 0.07204869, 0.4215464 ]],
[[ 0.6454156 , 0.84189773, 0.10041234],
[ 0.89345407, 0.60821944, 0.56667495],
[ 0.62806529, 0.67642623, 0.4951494 ],
[ 0.85371262, 0.13159418, 0.3402876 ]],
[[ 0.39828625, 0.50659049, 0.34835485],
[ 0.06839356, 0.74652916, 0.5722388 ],
[ 0.20762053, 0.0692997 , 0.02790474],
[ 0.84786427, 0.98461425, 0.19105092]],
[[ 0.36976317, 0.44268745, 0.23061621],
[ 0.47827819, 0.43044546, 0.90150601],
[ 0.2307732 , 0.61590552, 0.82066673],
[ 0.49611789, 0.4480612 , 0.46685895]],
[[ 0.40907925, 0.15996945, 0.05480348],
[ 0.70230347, 0.00926704, 0.97775948],
[ 0.19834276, 0.20127937, 0.44351548],
[ 0.48512974, 0.07319999, 0.5580616 ]],
[[ 0.35749629, 0.88443983, 0.55465496],
[ 0.61600298, 0.08260803, 0.4010818 ],
[ 0.40910226, 0.31984288, 0.50188118],
[ 0.34836289, 0.14394118, 0.06841569]]], dtype=float32)
希望有幫助
按照@JohnZwinck 在評論中的建議,將圖層添加到 2D 數組。
#data_in 是形狀為(14,n,m) 的原始數據 #循環涉及一次取一層(並應用適用的函數),然后將生成的二維數組存儲到列表中:
這是有效的解決方案:
new_list = []
for i in range(0,14): #looping 14 times (or equivalent to size of dimension considered)
print (i)
print (data_in[i,:,:].shape) #Choosing a level makes it a 2D array
#(so, the shape at this stage will be (n,m))
new_list.append(data_in)
final_list = np.dstack(new_list)
#In case the final dimension gets added as the last dimension, do this:
a = np.empty((14,n,m))
final_list = np.transpose(a, (0,1,2))
print (final_list.shape)
如果您的數組只是“列表”,則 sumplt 在開頭定義一個空列表並將項目附加到其中: foo=[] for i in range(14): ... foo.append(tab)
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