如何根據Unity中NGUI Slider的值移動transform.y？

Question

我正在制作一個游戲，必須用叉車撿起一些物體，我編寫此代碼來執行此操作，但無法正常工作。 拾取物體后未達到所需的位置...

public UISlider Slider;
public GameObject Lifter;
public float temp;


// Use this for initialization
void Start () {

}

// Update is called once per frame
void Update () {
    temp = Slider.GetComponent<UISlider> ().value;
    if (Slider.GetComponent<UISlider> ().value == 0) {
        Lifter.transform.position = new Vector3 (Lifter.transform.position.x, transform.position.y + temp - 1.2f, Lifter.transform.position.z);
    } 
    else 
    {
        Lifter.transform.position = new Vector3 (Lifter.transform.position.x, 0.39, Lifter.transform.position.z);
    }
}

Answer 1

僅當滑塊值為0（不正確）時才使用滑塊值。 嘗試使用此代碼-

public Slider MySlider;
public GameObject Lifter;
public float temp;

private float LifterInitialY = 0f;

// Use this for initialization
void Start () {
    LifterInitialY = Lifter.transform.position.y;
}

// Update is called once per frame
void Update () {
    Lifter.transform.position = new Vector3 (Lifter.transform.position.x, LifterInitialY + MySlider.value , Lifter.transform.position.z);
}

編輯：當滑塊值變為1時，將前叉向上（Y軸）移動-

添加測量值變量-

...
private float LifterInitialY = 0f;
private float someMeasuredValue = 0f;
...

並在Update方法中添加對滑塊值的檢查-

void Update () {
    if(MySlider.value >= 1f){
        someMeasuredValue = 1.2f; // measure some value
    }else{
        someMeasuredValue = 0f;
    }
    Lifter.transform.position = new Vector3 (Lifter.transform.position.x, LifterInitialY + MySlider.value + someMeasuredValue , Lifter.transform.position.z);
}