劇情：按多只大熊貓分組

Question

id  date        load          Instant  DayType  Month  Day  sort
0   2013-02-02  4667.341595   46       6        2      2    4667.341595
1   2013-02-02  4620.702889   47       6        2      2    4620.702889
2   2013-05-12  -4439.333624  3        0        5      12   4439.333624
3   2013-05-12  -4409.947044  4        0        5      12   4409.947044
4   2013-05-12  -4369.322473  5        0        5      12   4369.322473

嗨，我有一個功能rmse：

def RMSE2(x):
    return(np.sqrt(np.mean(x**2)))

負載是我們的x，我想繪制每一天類型的每個瞬時的均方根值的收益，這意味着我想在x瞬時和y中具有我的函數的收益以及7個不同的圖（每個daytype的一個圖）。

Answer 1

那是你要的嗎 ？

df.groupby('DayType')['load'].apply(lambda x:np.sqrt(np.mean(x**2)))

輸出：

DayType
0    4406.294544
6    4644.080789
Name: load, dtype: float64

Answer 2

columns = np.unique(final.DayType)
b = []
for i in columns:
    daytype = final[final['DayType'] == i]
    a = daytype[['load']].groupby(daytype['Instant']).apply(RMSE2)
    b.append(a)


import matplotlib.pyplot as plt
plt.xticks(rotation=70)
fig_size = plt.rcParams["figure.figsize"]
fig_size[0] = 8
fig_size[1] = 8
for i in range(9):
    x = range(48)  


    y = b[i]['load']
    plt.plot(x,y)

    plt.ylabel("Rmse")
    plt.xlabel("Day")

    plt.legend(range(9),loc="upper left", bbox_to_anchor=[0, 1],
           ncol=2, shadow=True, title="Legend", fancybox=True)




plt.show()