[英]Aggregate on a daily basis in R
我借用此處給出的可復制示例:
因為它與我想做的非常接近。
Interval value
1 2012-06-10 552
2 2012-06-11 4850
3 2012-06-12 4642
4 2012-06-13 4132
5 2012-06-14 4190
6 2012-06-15 4186
7 2012-06-16 1139
8 2012-06-17 490
9 2012-06-18 5156
10 2012-06-19 4430
11 2012-06-20 4447
12 2012-06-21 4256
13 2012-06-22 3856
14 2012-06-23 1163
15 2012-06-24 564
16 2012-06-25 4866
17 2012-06-26 4421
18 2012-06-27 4206
19 2012-06-28 4272
20 2012-06-29 3993
21 2012-06-30 1211
22 2012-07-01 698
23 2012-07-02 5770
24 2012-07-03 5103
25 2012-07-04 775
26 2012-07-05 5140
27 2012-07-06 4868
28 2012-07-07 1225
29 2012-07-08 671
30 2012-07-09 5726
31 2012-07-10 5176
在他的問題中,他要求每周匯總一次,我想做的是“每周一次”匯總。
因此,我想擁有一張類似於該表的表,並添加一周中同一天的值:
Day of the week value
1 "Sunday" 60000
2 "Monday" 50000
3 "Tuesday" 60000
4 "Wednesday" 50000
5 "Thursday" 60000
6 "Friday" 50000
7 "Saturday" 60000
我們可以使用weekdays
按周間隔對它們進行分組:
library(dplyr)
df %>%
group_by(Day_Of_The_Week = weekdays(as.Date(Interval))) %>%
summarise(value = sum(value))
# Day_Of_The_Week value
# <chr> <int>
#1 Friday 16903
#2 Monday 26368
#3 Saturday 4738
#4 Sunday 2975
#5 Thursday 17858
#6 Tuesday 23772
#7 Wednesday 13560
你可以試試:
aggregate(d$value, list(weekdays(as.Date(d$Interval))), sum)
我們可以使用data.table
來做到這data.table
library(data.table)
setDT(df1)[, .(value = sum(value)), .(Dayofweek = weekdays(as.Date(Interval)))]
# Dayofweek value
#1: Sunday 2975
#2: Monday 26368
#3: Tuesday 23772
#4: Wednesday 13560
#5: Thursday 17858
#6: Friday 16903
#7: Saturday 4738
使用lubridate https://cran.r-project.org/web/packages/lubridate/vignettes/lubridate.html
df1$Weekday=wday(arrive,label=TRUE)
library(data.table)
df1=data.table(df1)
df1[,sum(value),Weekday]
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