在Swift中對字典進行排序

Question

我從響應中獲取數組如下

  items=[{
         "displayName": "Adam Codo",
         "postedTime": "2011-04-04T21:31:20.000Z",
         "message" : "Hello Test Message"
         },
         {
         "displayName": "Leena",
         "postedTime": "2011-04-04T20:32:20.000Z",
         "message" : " Start Hello Test Message"
         },
         {
         "displayName": "Zohn",
         "postedTime": "2011-04-03T22:47:20.000Z",
         "message" : "Hi Leena"
         },
         {
         "displayName": "Leena",
         "postedTime": "2011-04-04T21:32:20.000Z",
         "message" : " Start Hello Test Message"
         },
         {
         "displayName": "Adam Codo",
         "postedTime": "2011-04-04T22:13:10.000Z",
         "message" : "Hello Test Message"
         }]

我已經按名稱對數組進行排序，之后又按時間對數組進行了排序。 所以我需要像下面這樣的排序數組

  items=[
         {
         "displayName": "Adam Codo",
         "postedTime": "2011-04-04T22:13:10.000Z",
         "message" : "Hello reply Test Message"
         },
         {
         "displayName": "Adam Codo",
         "postedTime": "2011-04-04T21:31:20.000Z",
         "message" : "Hello Test Message"
         },
         {
         "displayName": "Leena",
         "postedTime": "2011-04-04T21:32:20.000Z",
         "message" : " Start Hello Test Message"
         },
         {
         "displayName": "Leena",
         "postedTime": "2011-04-04T20:32:20.000Z",
         "message" : " Start Hello Test Message"
         },
         {
         "displayName": "Zohn",
         "postedTime": "2011-04-03T22:47:20.000Z",
         "message" : "Hi Leena"
         }
]

誰能建議我該怎么做？ 任何想法都很棒。

Answer 1

不要使用字典

相反，建立自己的模型，生活會更輕松。

這是模特

struct Element {
    let displayName: String
    let postedTime: Date
    let message: String

    init?(dict:[String:String]) {
        let dateFormatter = DateFormatter()
        dateFormatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSXXXXX"
        guard
            let displayName = dict["displayName"],
            let timeText = dict["postedTime"],
            let postedTime = dateFormatter.date(from: timeText),
            let message = dict["message"]
            else { return nil }

        self.displayName = displayName
        self.postedTime = postedTime
        self.message = message
    }
}

現在讓它變得Comparable

extension Element: Comparable {

    static func <(lhs: Element, rhs: Element) -> Bool {
        if lhs.displayName != rhs.displayName {
            return lhs.displayName < rhs.displayName
        }
        return lhs.postedTime < rhs.postedTime
    }

    static func ==(lhs: Element, rhs: Element) -> Bool {
        return lhs.displayName == rhs.displayName && lhs.postedTime < rhs.postedTime
    }

}

現在給出您的字典數組

let items = [
    [
        "displayName": "Adam Codo",
        "postedTime": "2011-04-04T21:31:20.000Z",
        "message" : "Hello Test Message"
    ],
    [
        "displayName": "Leena",
        "postedTime": "2011-04-04T20:32:20.000Z",
        "message" : " Start Hello Test Message"
    ],
    [
        "displayName": "Zohn",
        "postedTime": "2011-04-03T22:47:20.000Z",
        "message" : "Hi Leena"
    ],
    [
        "displayName": "Leena",
        "postedTime": "2011-04-04T21:32:20.000Z",
        "message" : " Start Hello Test Message"
    ],
    [
        "displayName": "Adam Codo",
        "postedTime": "2011-04-04T22:13:10.000Z",
        "message" : "Hello Test Message"
    ]
]

我們可以將其轉換為一個元素數組，最后對其進行排序

let sortedElms = items.flatMap(Element.init).sorted()

結果

[
    Element(displayName: "Adam Codo", postedTime: 2011-04-04 21:31:20 +0000, message: "Hello Test Message"),
    Element(displayName: "Adam Codo", postedTime: 2011-04-04 22:13:10 +0000, message: "Hello Test Message"),
    Element(displayName: "Leena", postedTime: 2011-04-04 20:32:20 +0000, message: " Start Hello Test Message"),
    Element(displayName: "Leena", postedTime: 2011-04-04 21:32:20 +0000, message: " Start Hello Test Message"),
    Element(displayName: "Zohn", postedTime: 2011-04-03 22:47:20 +0000, message: "Hi Leena")
]

Answer 2

var sortedResults = items.sorted {
          (dictOne, dictTwo) -> Bool in 

    if dictOne["displayName"]! != dictTwo["displayName"]! {
            return dictOne["displayName"]! < dictTwo["displayName"]!
        }

        return dictOne["postedTime"]! < dictTwo["postedTime"]!
        };

Answer 3

NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc]
                                    initWithKey: @"displayName" ascending: YES];

NSArray *sortedArray = [_locations sortedArrayUsingDescriptors:[NSArray arrayWithObject:sortDescriptor]];

NSArray *sortedLocations = [_locations sortedArrayUsingComparator: ^(NSDictionary *d1, NSDictionary *d2) {
    ISO8601DateFormatter *formatter = [[ISO8601DateFormatter alloc] init];
    NSDate *theDate1 = [formatter dateFromString:[d1 valueForKey:@"postedTime"]];
    NSDate *theDate2 = [formatter dateFromString:[d2 valueForKey:@"postedTime"]];
    return [theDate1 compare:theDate2];
}];

要么

NSArray *sortedLocations = [_locations sortedArrayUsingComparator: ^(NSDictionary *d1, NSDictionary *d2) {

    ISO8601DateFormatter *formatter = [[ISO8601DateFormatter alloc] init];
    NSDate *theDate1 = [formatter dateFromString:[d1 valueForKey:@"postedTime"]];
    NSDate *theDate2 = [formatter dateFromString:[d2 valueForKey:@"postedTime"]];

    NSString *name1 = [d1 valueForKey:@"displayName"];
    NSString *name2 = [d2 valueForKey:@"displayName"];

    if ([name1 compare:name2]) {
        return [theDate1 compare:theDate2];
    }


    return NSOrderedDescending;
}];

但是請問我沒有檢查