沒有空格的單詞之間未檢測到標點符號

Question

當檢測到標點（。？！）並且出現在兩個單詞之間且沒有空格時，如何拆分句子？

例：

>>> splitText = re.split("(?<=[.?!])\s+", "This is an example. Not 
    working as expected.Because there isn't a space after dot.")  

輸出：

['This is an example.', 
"Not working as expected.Because there isn't a space after dot."] 

預期：

['This is an example.', 
'Not working as expected.', 
'Because there isn't a space after dot.']`

Answer 1

splitText = re.split("[.?!]\s*", "This is an example. Not working as expected.Because there isn't a space after dot.")

+表示1個或多個，*表示0個或多個。

如果您需要保留。 您可能不想拆分，但可以這樣做：

splitText = re.findall(".*?[.?!]", "This is an example. Not working as expected.Because there isn't a space after dot.")

這使

['This is an example.',
 ' Not working as expected.',
 "Because there isn't a space after dot."]

您可以通過使用正則表達式（例如'\\s*.*?[.?!]' ）或僅使用.trim()來.trim()

Answer 2

使用https://regex101.com/r/icrJNl/3/ 。

import re
from pprint import pprint

split_text = re.findall(".*?[?.!]", "This is an example! Working as "
                        "expected?Because.")

pprint(split_text)

注意： .*? 是一個懶惰（或非貪婪）量詞，與.*相反，它是一個貪婪量詞。

輸出：

['This is an example!', 
 ' Working as expected?', 
 'Because.']

另一個解決方案：

import re
from pprint import pprint

split_text = re.split("([?.!])", "This is an example! Working as "
    "expected?Because.")

pprint(split_text)

輸出：

['This is an example', 
'!', 
' Working as expected', 
'?', 
'Because', 
'.', 
'']