使用jq從其他數組派生一個數組（請參閱Python列表推導）

Question

給定以下json，其中包含兩個數組：

{"zones":["dev01","dev02","dev03","dev04","dev05","dev06","dev07","dev08","dev09","dev10","dev11","dev12","dev13","dev14","dev15","dev16","dev17","dev18","dev19","dev20"],"disabled_zones":["dev01","dev05","dev06","dev08","dev10","dev11","dev12","dev13","dev14","dev15","dev16","dev17","dev18","dev19","dev20"]}

我希望派生第三個數組，其中包含在第一個數組中出現但不在第二個數組中的項：

{"enabled_zones":["dev02","dev03","dev04","dev07","dev09"]}

我想使用jq完成此任務

在python中，我將使用列表推導來實現此目的：

>>> zones = ["dev01","dev02","dev03","dev04","dev05","dev06","dev07","dev08","dev09","dev10","dev11","dev12","dev13","dev14","dev15","dev16","dev17","dev18","dev19","dev20"]
>>> disabled_zones = ["dev01","dev05","dev06","dev08","dev10","dev11","dev12","dev13","dev14","dev15","dev16","dev17","dev18","dev19","dev20"]
>>> enabled_zones = [x for x in zones if x not in disabled_zones]
>>> print(enabled_zones)
['dev02', 'dev03', 'dev04', 'dev07', 'dev09']

我目前正在嘗試使用foreach array1中的項目，並使用in檢查它們是否存在於array2中in但是我在語法上苦苦掙扎。

我如何使用jq實現呢？

Answer 1

從jq手冊 ：

除了對數字進行常規算術減法外，-運算符還可用於數組，以從第一個數組中刪除所有出現的第二個數組元素。

這會做：

jq '{ "enabled_zones": (.zones - .disabled_zones) }' data.json