如何將var同時視為int和string。

Question

def die():
    first = str(randint(1, 6))
    second = str(randint(1, 6))
    total = first + second
    print "You have rolled a " + first + " and a " + second + ", for a total score of " + total + "."

標准的擲骰子游戲，但是我很難打印單個骰子的值以及總數。 將其視為單個字符串，然后求和會導致串聯，而不是實際求和。

謝謝

Answer 1

將變量保留為數字，並讓print執行格式化：

def die():
    first = randint(1, 6)
    second = randint(1, 6)
    total = first + second
    print "You have rolled a", first, "and a", second, ", for a total score of", total, "."

或者，您可以使用str.format進行一些格式化，以str.format地控制上述默認參數間的間距：

print "You have rolled a {} and a {}, for a \
total score of {}.".format(first, second, total)

Answer 2

有兩種方法可以解決您的問題（還有更多方法！）。 首先，您需要確保將整數加在一起時將整數保留為int類型，然后在打印出來時將其轉換為字符串。

您可以使用str()強制轉換方法和+級聯，如下所示進行操作。

def die1():
    """Roll and print two dice using concat."""
    first = randint(1, 6) # keep these as integers
    second = randint(1, 6)
    total = first + second # so addition works
    # but now cast to str when printing
    print "You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + str(total) + "."

但是更方便的方法是使用str.format()方法在字符串中放置占位符，然后讓python為您str.format()和格式化整數值。 如果您有4個或更多數字的大數字，那么這樣做的好處是，您可以使用字符串格式代碼，例如"my big number: {0:d,}".format(1000000)以使字符串輸出類似於"my big number: 1,000,000" ，可讀性更高。

def die2():
    """Roll and print two dice using str.format()."""
    first = randint(1, 6)
    second = randint(1, 6)
    total = first + second
    # or use the str.format() method, which does this for you
    print "You have rolled a {0} and a {1}, for a total score of {3}.".format(first, second, total)

Answer 3

您可以使用強制轉換來更改var的結構。 您既可以將它們用作字符串，也可以使用以下代碼行：

 total = int(first) + int(second)

或將它們用作int並通過使用str（first）和str（second）將它們轉換為打印結果中的字符串

最好

Answer 4

print "You have rolled a " + str(first)這會將int轉換為字符串，從而將其連接起來。

此外，您可以執行total = int(first) + int(second)解決第一個問題。

Answer 5

您有兩種解決方案：

1. 在添加數字之前將其轉換回int ：

    def die(): first = str(randint(1, 6)) second = str(randint(1, 6)) total = str(int(first) + int(second)) print ("You have rolled a " + first + " and a " + second + ", for a total score of " + total + ".") 

2. 在打印數字之前將其轉換為str ：

    def die(): first = randint(1, 6) second = randint(1, 6) total = first + second print ("You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + str(total) + ".") 

兩種解決方案都可以正常工作。

Answer 6

這也將起作用。 在對它們執行求和之前，請勿將first和second轉換為str 。 然后記住在print語句中將它們轉換為str 。

def die():
    first = randint(1, 6)
    second = randint(1, 6)
    total = str(first + second)
    print ("You have rolled a " + str(first) + " and a " + str(second) + ", for a total score of " + total + ".")