Python數組組數

Question

在Python中，我有一系列

("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")

我需要通過顯示計數來輸出

("192.168.1.1","high",2),("192.168.1.1","low",2),("192.168.1.2","high",1),("192.168.1.2","medium",1)

任何人請幫助我

Answer 1

您可以使用集合中的計數器。

from collections import Counter

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

counter = Counter(l)

result = [(*key, counter[key]) for key in counter]

Answer 2

如果您不關心訂單：

l = [("192.168.1.1","high"),("192.168.1.1","high"),("192.168.1.1","low"),("192.168.1.1","low"),("192.168.1.2","high"),("192.168.1.2","medium")]

list(set([(*t, l.count(t)) for t in l]))