[英]Generate random JSON structure permutations for a data set
我想生成許多不同的JSON結構排列作為同一數據集的表示,最好不必硬編碼實現。 例如,給定以下JSON:
{"name": "smith", "occupation": "agent", "enemy": "humanity", "nemesis": "neo"}`
應該產生許多不同的排列,例如:
{"name":"smith"}- > {"last_name":"smith"}
{"name":"...","occupation":"..."} -> {"occupation":"...", "name":"..."}
{"name":"...","occupation":"..."} -> "smith":{"occupation":"..."}
{"name":"...","occupation":"..."} -> "status": 200, "data":{"name":"...","occupation":"..."}
目前,實施情況如下:
我使用itertools.permutations
和OrderedDict()來調整可能的鍵和相應的值組合以及它們返回的順序。
key_permutations = SchemaLike(...).permutate()
all_simulacrums = []
for key_permutation in key_permutations:
simulacrums = OrderedDict(key_permutation)
all_simulacrums.append(simulacrums)
for x in itertools.permutations(all_simulacrums.items()):
test_data = json.dumps(OrderedDict(p))
print(test_data)
assert json.loads(test_data) == data, 'Oops! {} != {}'.format(test_data, data)
當我嘗試實現排列和模板的排列時,我的問題就出現了。 我不知道如何最好地實現這個功能,任何建議?
如需訂購,只需使用有序的dicts:
>>> data = OrderedDict(foo='bar', bacon='eggs', bar='foo', eggs='bacon')
>>> for p in itertools.permutations(data.items()):
... test_data = json.dumps(OrderedDict(p))
... print(test_data)
... assert json.loads(test_data) == data, 'Oops! {} != {}'.format(test_data, data)
{"foo": "bar", "bacon": "eggs", "bar": "foo", "eggs": "bacon"}
{"foo": "bar", "bacon": "eggs", "eggs": "bacon", "bar": "foo"}
{"foo": "bar", "bar": "foo", "bacon": "eggs", "eggs": "bacon"}
{"foo": "bar", "bar": "foo", "eggs": "bacon", "bacon": "eggs"}
{"foo": "bar", "eggs": "bacon", "bacon": "eggs", "bar": "foo"}
{"foo": "bar", "eggs": "bacon", "bar": "foo", "bacon": "eggs"}
{"bacon": "eggs", "foo": "bar", "bar": "foo", "eggs": "bacon"}
{"bacon": "eggs", "foo": "bar", "eggs": "bacon", "bar": "foo"}
{"bacon": "eggs", "bar": "foo", "foo": "bar", "eggs": "bacon"}
{"bacon": "eggs", "bar": "foo", "eggs": "bacon", "foo": "bar"}
{"bacon": "eggs", "eggs": "bacon", "foo": "bar", "bar": "foo"}
{"bacon": "eggs", "eggs": "bacon", "bar": "foo", "foo": "bar"}
{"bar": "foo", "foo": "bar", "bacon": "eggs", "eggs": "bacon"}
{"bar": "foo", "foo": "bar", "eggs": "bacon", "bacon": "eggs"}
{"bar": "foo", "bacon": "eggs", "foo": "bar", "eggs": "bacon"}
{"bar": "foo", "bacon": "eggs", "eggs": "bacon", "foo": "bar"}
{"bar": "foo", "eggs": "bacon", "foo": "bar", "bacon": "eggs"}
{"bar": "foo", "eggs": "bacon", "bacon": "eggs", "foo": "bar"}
{"eggs": "bacon", "foo": "bar", "bacon": "eggs", "bar": "foo"}
{"eggs": "bacon", "foo": "bar", "bar": "foo", "bacon": "eggs"}
{"eggs": "bacon", "bacon": "eggs", "foo": "bar", "bar": "foo"}
{"eggs": "bacon", "bacon": "eggs", "bar": "foo", "foo": "bar"}
{"eggs": "bacon", "bar": "foo", "foo": "bar", "bacon": "eggs"}
{"eggs": "bacon", "bar": "foo", "bacon": "eggs", "foo": "bar"}
相同的原則可以應用於鍵/值排列:
>>> for p in itertools.permutations(data.keys()):
...: test_data = json.dumps(OrderedDict(zip(p, data.values())))
...: print(test_data)
...:
{"foo": "bar", "bacon": "eggs", "bar": "foo", "eggs": "bacon"}
{"foo": "bar", "bacon": "eggs", "eggs": "foo", "bar": "bacon"}
{"foo": "bar", "bar": "eggs", "bacon": "foo", "eggs": "bacon"}
{"foo": "bar", "bar": "eggs", "eggs": "foo", "bacon": "bacon"}
{"foo": "bar", "eggs": "eggs", "bacon": "foo", "bar": "bacon"}
{"foo": "bar", "eggs": "eggs", "bar": "foo", "bacon": "bacon"}
{"bacon": "bar", "foo": "eggs", "bar": "foo", "eggs": "bacon"}
{"bacon": "bar", "foo": "eggs", "eggs": "foo", "bar": "bacon"}
{"bacon": "bar", "bar": "eggs", "foo": "foo", "eggs": "bacon"}
{"bacon": "bar", "bar": "eggs", "eggs": "foo", "foo": "bacon"}
{"bacon": "bar", "eggs": "eggs", "foo": "foo", "bar": "bacon"}
{"bacon": "bar", "eggs": "eggs", "bar": "foo", "foo": "bacon"}
{"bar": "bar", "foo": "eggs", "bacon": "foo", "eggs": "bacon"}
{"bar": "bar", "foo": "eggs", "eggs": "foo", "bacon": "bacon"}
{"bar": "bar", "bacon": "eggs", "foo": "foo", "eggs": "bacon"}
{"bar": "bar", "bacon": "eggs", "eggs": "foo", "foo": "bacon"}
{"bar": "bar", "eggs": "eggs", "foo": "foo", "bacon": "bacon"}
{"bar": "bar", "eggs": "eggs", "bacon": "foo", "foo": "bacon"}
{"eggs": "bar", "foo": "eggs", "bacon": "foo", "bar": "bacon"}
{"eggs": "bar", "foo": "eggs", "bar": "foo", "bacon": "bacon"}
{"eggs": "bar", "bacon": "eggs", "foo": "foo", "bar": "bacon"}
{"eggs": "bar", "bacon": "eggs", "bar": "foo", "foo": "bacon"}
{"eggs": "bar", "bar": "eggs", "foo": "foo", "bacon": "bacon"}
{"eggs": "bar", "bar": "eggs", "bacon": "foo", "foo": "bacon"}
等等......如果您不需要所有組合,則可以使用一組預定義的鍵/值。 您還可以使用帶有random.choice
的for
循環來翻轉硬幣以跳過某些組合或使用random.shuffle
冒着重復組合的風險。
對於模板,我猜你必須創建一個不同模板的列表(或列表列表,如果你想要嵌套結構),然后迭代它以創建你的數據。 為了給出更好的建議,我們需要對您想要的更加有限的規范。
請注意,有幾個庫在Python中生成測試數據:
>>> from faker import Faker
>>> faker = Faker()
>>> faker.credit_card_full().strip().split('\n')
['VISA 13 digit', 'Jerry Gutierrez', '4885274641760 04/24', 'CVC: 583']
Faker有幾個模式,很容易創建自己的自定義虛假數據提供程序。
由於dict命令的shuffle已經被回答,我將跳過它。
當新的事物浮現在腦海中時,我會補充這個答案。
from random import randint
from collections import OrderedDict
#Randomly shuffles the key-value pairs of a dictionary
def random_dict_items(input_dict):
items = input_dict.items()
new_dict = OrderedDict()
for i in items:
rand = randint(0, 1)
if rand == 0:
new_dict[i[0]] = i[1]
else:
new_dict[i[1]] = i[0]
return new_dict
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