如果該列包含另一個數據框的列中的字符串，則在該數據框中創建一個新列

Question

如果該列包含第二個數據框的列中的任何值，我想在數據框中創建一個新列。

第一個數據框

WXYnineZAB
EFGsixHIJ
QRSeightTUV
GHItwoJKL
YZAfiveBCD
EFGsixHIJ
MNOthreePQR
ABConeDEF
MNOthreePQR
MNOthreePQR
YZAfiveBCD
WXYnineZAB
GHItwoJKL
KLMsevenNOP
EFGsixHIJ
ABConeDEF
KLMsevenNOP
QRSeightTUV
STUfourVWX
STUfourVWX
KLMsevenNOP
WXYnineZAB
CDEtenFGH
YZAfiveBCD
CDEtenFGH
QRSeightTUV
ABConeDEF
STUfourVWX
CDEtenFGH
GHItwoJKL

第二個數據框

one
three
five
seven
nine

輸出數據框

WXYnineZAB,nine
EFGsixHIJ,***
QRSeightTUV,***
GHItwoJKL,***
YZAfiveBCD,five
EFGsixHIJ,***
MNOthreePQR,three
ABConeDEF,one
MNOthreePQR,three
MNOthreePQR,three
YZAfiveBCD,five
WXYnineZAB,nine
GHItwoJKL,***
KLMsevenNOP,seven
EFGsixHIJ,***
ABConeDEF,one
KLMsevenNOP,seven
QRSeightTUV,***
STUfourVWX,***
STUfourVWX,***
KLMsevenNOP,seven
WXYnineZAB,nine
CDEtenFGH,***
YZAfiveBCD,five
CDEtenFGH,***
QRSeightTUV,***
ABConeDEF,one
STUfourVWX,***
CDEtenFGH,***
GHItwoJKL,***

為了易於解釋，我將第一個數據幀設置為3chars +搜索字符串+ 3chars，但是我的實際文件沒有這樣的一致性。

Answer 1

源DF：

In [172]: d1
Out[172]:
            txt
0    WXYnineZAB
1     EFGsixHIJ
2   QRSeightTUV
3     GHItwoJKL
4    YZAfiveBCD
..          ...
25  QRSeightTUV
26    ABConeDEF
27   STUfourVWX
28    CDEtenFGH
29    GHItwoJKL

[30 rows x 1 columns]

In [173]: d2
Out[173]:
    word
0    one
1  three
2   five
3  seven
4   nine

從第二個DataFrame生成RegEx模式：

In [174]: pat = r'({})'.format(d2['word'].str.cat(sep='|'))

In [175]: pat
Out[175]: '(one|three|five|seven|nine)'

提取與RegEx模式匹配的單詞並將其分配為新列：

In [176]: d1['new'] = d1['txt'].str.extract(pat, expand=False)

In [177]: d1
Out[177]:
            txt   new
0    WXYnineZAB  nine
1     EFGsixHIJ   NaN
2   QRSeightTUV   NaN
3     GHItwoJKL   NaN
4    YZAfiveBCD  five
..          ...   ...
25  QRSeightTUV   NaN
26    ABConeDEF   one
27   STUfourVWX   NaN
28    CDEtenFGH   NaN
29    GHItwoJKL   NaN

[30 rows x 2 columns]

您也可以在同一步驟中填寫NaN：

In [178]: d1['new'] = d1['txt'].str.extract(pat, expand=False).fillna('***')

In [179]: d1
Out[179]:
            txt   new
0    WXYnineZAB  nine
1     EFGsixHIJ   ***
2   QRSeightTUV   ***
3     GHItwoJKL   ***
4    YZAfiveBCD  five
..          ...   ...
25  QRSeightTUV   ***
26    ABConeDEF   one
27   STUfourVWX   ***
28    CDEtenFGH   ***
29    GHItwoJKL   ***

[30 rows x 2 columns]

Answer 2

如果要避免使用RegEx，請使用以下純粹基於列表的解決方案：

# Sample DataFrames (structure is borrowed from MaxU)
d1 = pd.DataFrame({'txt':['WXYnineZAB','EFGsixHIJ','QRSeightTUV','GHItwoJKL']})
d2 = pd.DataFrame({'word':['two','six']})
# Check if word exists in any txt (1-liner).
exists = [list(d2.word[[word in txt for word in d2.word]])[0] if sum([word in txt for word in d2.word]) == 1 else '***' for txt in d1.txt]
# Resulting output
res = pd.DataFrame(zip(d1.txt,exists), columns = ['text','word'])

結果：

          text word
0   WXYnineZAB  ***
1    EFGsixHIJ  six
2  QRSeightTUV  ***
3    GHItwoJKL  two