如何剝離[]中的所有內容

Question

我試圖刪除[]內的主要文本，包括[] ，如下所示

title  = "[test][R] D123/Peace123456: panic:"
print title
title = title.strip('[.*]')
print title

輸出： -

test][R] D123/Peace123456: panic:

預期產量：

[R] D123/Peace123456: panic:

Answer 1

你需要非貪婪的Regex來匹配first []從開始，而re.sub來進行替換：

In [10]: title  = "[test][R] D123/Peace123456: panic:"

# `^\[[^]]*\]` matches `[` followed by any character
# except `]` zero or more times, followed by `]`
In [11]: re.sub(r'^\[[^]]*\]', '', title)
Out[11]: '[R] D123/Peace123456: panic:'

# `^\[.*?\]` matches `[`, followed by any number of
# characters non-greedily by `.*?`, followed by `]`
In [12]: re.sub(r'^\[.*?\]', '', title)
Out[12]: '[R] D123/Peace123456: panic:'