[英]Trying to Remove the First 3 and Last 6 Characters from Each Item in a List
[英]How to strip everything but the first 2 characters for each item in a list?
我正在使用從包含多個配置文件的目錄生成的列表。 所有配置文件都遵循相同的命名約定,它們以兩個字母開頭,后跟 2-3 個數字並以.conf 結尾
aa01.conf, aa02.conf, aa03.conf, bb01.conf, bb02.conf,...zz99.conf, zz100.conf
我只對每個文件開頭的兩個字母感興趣。 如何去除數字“.conf”,然后從結果中刪除所有重復項?
如果您只想要前兩個字符:
list_1 = ['aa01.conf', 'aa02.conf', 'aa03.conf', ... 'zz99.conf', 'zz100.conf']
list_2 = [item[:2] for item in list_1]
刪除重復項
list_3 = list(set(list_2))
要擁有前兩個字符和擴展名,您可以執行以下操作
your_list = ["aa01.conf", "aa02.conf", "aa03.conf", "bb01.conf", "bb02.conf"]
your_list_with_out_duplicates = list(set(your_list))
your_lis_of_first_two_char = [
f"{x[:2]}.{x[-4:]}" for x in your_list_with_out_duplicates
]
print(your_lis_of_first_two_char)
output
['bb.conf', 'aa.conf', 'aa.conf', 'aa.conf', 'bb.conf']
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