[英]Parse Wiley Online Library
我想從Ullmann的《使用Python和BeautifulSoup 的工業化學百科全書》中提取所有章節的DOI。
所以從
<h2 class="meta__title meta__title__margin"><span class="hlFld-Title"><a href="/doi/10.1002/14356007.c01_c01.pub2">Aerogels</a></span></h2>
我想獲得“ Aerogels”和“ /doi/full/10.1002/14356007.c01_c01.pub2”
更大的樣本:
<ul class="chapter_meta meta__authors rlist--inline comma">
<li><span class="hlFld-ContribAuthor"><a href="/action/doSearch?ContribAuthorStored=H%C3%BCsing%2C+Nicola"><span>Nicola Hüsing</span></a></span></li>
<li><span class="hlFld-ContribAuthor"><a href="/action/doSearch?ContribAuthorStored=Schubert%2C+Ulrich"><span>Ulrich Schubert</span></a></span></li>
</ul><span class="meta__epubDate"><span>First published: </span>15 December 2006</span><div class="content-item-format-links">
<ul class="rlist--inline separator">
<li><a title="Abstract" href="/doi/abs/10.1002/14356007.c01_c01.pub2">Abstract</a></li>
<li><a title="Full text" href="/doi/full/10.1002/14356007.c01_c01.pub2">
Full text
</a></li>
對於我嘗試過的標題:
span['hlFld-Title'].a
對於我嘗試過的DOI:
for link in soup.find_all('a'.title):
print(link.get('href'))
但是可悲的是我是一個傻瓜(傻瓜),它不起作用。
網址為https://onlinelibrary.wiley.com/browse/book/10.1002/14356007/title?startPage= {1..59}
謝謝你的幫助。
這是一個快速解決方案,將“ DOI; title”對打印到命令行:
import requests
from bs4 import BeautifulSoup
for i in range(59):
page = requests.get("https://onlinelibrary.wiley.com/browse/book/10.1002/14356007/title?startPage={}".format(i))
soup = BeautifulSoup(page.content, 'lxml')
content = soup.findAll("span", class_="hlFld-Title")
for c in content:
print(c.a.get('href')+";"+c.get_text())
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