[英]How would i generate a new random number
import random
guess = '0'
while (guess) != 'exit':
answer = random.randrange(1,100)
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
在您猜對了正確答案后,我將如何生成一個新的隨機數?
這里的主要問題是,即使您猜錯了,您實際上每次都會生成一個新的數字。 相反,您應該在循環之外生成第一個隨機數,並且僅在猜測正確的情況下才生成新的隨機數:
import random
guess = '0'
answer = random.randrange(1, 100)
while (guess) != 'exit':
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
answer = random.randrange(1, 100) #make new random number if guess is correct
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
我不確定我是否正確理解您的評論。 您可以使用random.randint(a,b)來獲取整數,而不是十進制數。
( https://docs.python.org/3/library/random.html#random.randint )
import random
guess = '0'
answer = random.randint(1, 100)
while (guess) != 'exit':
answer = str(answer)
guess = input('Enter a number between 1 and 100 or enter exit to exit: ')
if not guess.isdigit():
if guess == "exit":
print('Game closed')
break
else:
print('Your guess was not a digit, try again')
guess = (guess)
if guess == answer:
print('Correct')
answer = random.randint(1, 100) #make new random number if guess is correct
elif guess > answer :
print('Too high, try again')
elif guess < answer :
print('Too low, try again')
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